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iragen [17]
2 years ago
7

Solve this equation 2 (c+8) = -12

Mathematics
2 answers:
s2008m [1.1K]2 years ago
8 0

Answer:

c=-14

Step-by-step explanation:

vovikov84 [41]2 years ago
4 0

Answer:

C= -14

Step-by-step explanation:

2(c+8)= -12 > divide both sides by 2

C+8= -6 > move c by itself

C= -6-8  > then subtract -6 and -8 and you will get -14

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The difference of two numbers is 7. Their sum is 41. What is the smaller number?
kicyunya [14]
17 is the smaller number.
EXPLANATION:

The numbers are 24 and 17.

Difference of 7? Check.

Sum of 41? Check.

BOOM magic
8 0
3 years ago
find the equation of the axis of symmetry for this equation. f(x) = 6x^2 - 3x + 49. hint: to find the axis of symmetry, use equa
Olenka [21]

We want to find the axis of symmetry of the function;

f(x)=6x^2-3x+49

STEP 1:

The equation for the axis of symmetry of a line is given as;

x=-\frac{b}{2a}

From the equation, a = 6 and b = -3, so,

STEP 2: Insert the values of a and b into the equation to obtain;

x=-\frac{-3}{2\times6}=--\frac{3}{12}=+\frac{1}{4}

CONCLUSION:

Therefore, we see that the axis of symmetry is the line;

x=\frac{1}{4}

8 0
1 year ago
If x = 7 and y = 10, what is the value of the expression xy - ( y + 2) ?
BartSMP [9]

X=7 and y=10

Given that xy-(y+2)

Therefore,

7*10-(10+2)

70-12

58 Ans


7 0
3 years ago
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A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant
Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10

Similarly, but exchanging the role of x and y, we compute the length of BC:

\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5

So, the area of the rectangle is \overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3

\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4

So, the area of the portion located in the third quadrant is \overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12

This means that the ratio between the two area is

\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}

If we want this ratio to be a percentage, just make sure that the denominator is 100:

\cfrac{12}{50} = \cfrac{12}{50}\cdot \cfrac{2}{2} = \cfrac{24}{100} = 24\%

3 0
3 years ago
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