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iragen [17]
3 years ago
7

Solve this equation 2 (c+8) = -12

Mathematics
2 answers:
s2008m [1.1K]3 years ago
8 0

Answer:

c=-14

Step-by-step explanation:

vovikov84 [41]3 years ago
4 0

Answer:

C= -14

Step-by-step explanation:

2(c+8)= -12 > divide both sides by 2

C+8= -6 > move c by itself

C= -6-8  > then subtract -6 and -8 and you will get -14

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Please help!!! ASAP someone please
murzikaleks [220]

Answer:

0.31 yr

Step-by-step explanation:

The formula for interest compounded continuously is

FV = PVe^{rt}

FV = future value, and

PV = present value

If FV is twice the PV, we can calculate the doubling time, t

\begin{array}{rcl}2 & = & e^{rt}\\\ln 2 & = & rt\\t & = & \dfrac{\ln 2}{r} \\\end{array}

1. Brianna's doubling time

\begin{array}{rcl}t & = & \dfrac{\ln 2}{0.065}\\\\& = & \textbf{10.663 yr}\\\end{array}

2. Adam's doubling time

The formula for interest compounded periodically is

FV = PV\left (1 + \dfrac{r}{n} \right )^{nt}

where

n = the number of payments per year

If FV is twice the PV, we can calculate the doubling time.

\begin{array}{rcl}2 & = & \left (1 + \dfrac{0.0675}{4} \right )^{4t}\\\\&= & (1 + 0.016875 )^{4t}\\& = & 1.016875^{4t}\\\ln 2& = & 4 (\ln 1.01688)\times t \\& = & 0.066937t\\t& = & \dfrac{\ln 2}{0.066937}\\\\& = & \textbf{10.355 yr}\\\end{array}

3. Brianna's doubling time vs Adam's

10.663 - 10.355 = 0.31 yr

It would take 0.31 yr longer for Brianna's money to double than Adam's.

3 0
3 years ago
What is the original price if there is a 45% discount and the sale price is $550?
Svetradugi [14.3K]

Original price×(1-discount price)=new price or sale price so

Put x in original price...x(1-45/100)=550

So the original price is 1000

3 0
3 years ago
What is the equation of line q?<br> y=-2x + 5<br> y=0.5x + 7.5<br> y=-2x-5<br> y=0.5x - 7.5
Tasya [4]

Answer:

C, just got it on edgenuity.

Step-by-step explanation:

8 0
3 years ago
Estimate the following quantities without using a calculator. Then find a more precise result, using a calculator if necessary.
zubka84 [21]

Explanation:

a. It is so easy to double a number that no approximation is necessary.

  31,000 × 200 = 3.1×10⁴ × 2×10² = 6.2×10⁶ exactly

__

b. 6.2×10³ × 5.2×10⁶ ≈ 6×5×10⁹ = 3×10¹⁰ approximately

The approximation can be refined a bit by taking the ".2" into account:

  6.2×10³ × 5.2×10⁶ ≈ (6×5 + .2×(6+5))×10⁹

  = 32.2×10⁹ = 3.22×10¹⁰ approximately

Actual product: 3.224×10¹⁰.

For most purposes, the approximation is an adequate approximation, as it it within 10% of the actual value.

__

c. 9×10⁶ -2.3×10⁴ ≈ 9×10⁶ approximately

A better approximation is to actually subtract an approximation of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.02)×10⁶ ≈ 8.98×10⁶ approximately

The actual value uses all of the digits of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.023)×10⁶ = 8.977×10⁶ exactly

As in part B, either approximation is adequate for most purposes, as the difference from the actual value is less than .3%.

_____

The accuracy required of an approximation, hence the work you expend improving accuracy, should depend on the need in the final application of the number. Often, approximations are used for budget or resource planning purposes where some "slop" is allowed or even expected.

They can also be used in engineering applications, where the error needs to be on the side of more safety (rather than less).

7 0
3 years ago
1.
riadik2000 [5.3K]

Answer:

ī=80; s = 10

Step-by-step explanation:

When the standard deviation is from a finite group it is denoted by s. The number of transactions from an atm are countable in a day. So the standard deviation will be represented by s.

and ī represents the mean.

The other choices are incorrect because mean is usually represented by a bar over the alphabet such as x.

a simple alphabet does not denote the mean of the sample or population.

6 0
3 years ago
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