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2 years ago

Identify the initial amount a and the decay factor b in the exponential function. y equals 5 times 0.5 superscript x

1 answer:

Ber [7]2 years ago

7 0

$\bf \qquad \textit{Amount for Exponential Decay}
\\\\
A=a(b)^x\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
a=\textit{initial amount}\\
b=\textit{decay factor}\\
x=\textit{elapsed time}\\
\end{cases}
\\\\\\
y=\stackrel{a}{5}(\stackrel{b}{0.5})^x$

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SVETLANKA909090 [29]

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This shows that $y' = y$ is true when $y = e^x$

-----------------------

Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.

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2 years ago

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Rom4ik [11]

Answer:

C. -3/4, -2/3, 1/5

Step-by-step explanation:

Just from observation, you can tell the 1/5 will be the greatest because all the other fractions are negative. Then, I converted them to decimal form to make it easier.

-2/3 = -0.6666666 (the 6 goes on forever)

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Then, you put them in order.

-3/4 would be the least .

Followed by, -2/3

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