The Hardy-Weinberg equation is
p2 + 2pq + q2 = 1 and p + q = 1
p = frequency of the dominant allele in the population
q = frequency of the recessive allele in the population
p2 = percentage of homozygous dominant individuals
q2 = percentage of homozygous recessive individuals
2pq = percentage of heterozygous individuals
Here in this question, 20 out of 100 rabbits have white fur which means that the % of homozygous recessive individuals is
= 20/100 = 0.2
q2 = percentage of homozygous recessive individuals = 0.2
q = square root of 0.2
q = 0.44 = frequency of the recessive allele in the population = 44%