Which values are solutions to the inequality? 2r≤3r−8 Select each correct answer. 6 7 8 9

Mathematics

2 answers:

Artyom0805 [142]3 years ago

8 0

Answer:

The correct answers are 8 and 9.

Step-by-step explanation:

To solve an inequality you have to solve it like an equality, but when you obtain the solution you don´t have only one value but a set of values that fit into the solution, in this case, the solution to the inequality is:

$2r\leq 3r-8\\2r+8\leq3r\\8\leq3r-2r\\8\leq r$

The set of values found for the solution of this inequality indicates that r takes values greater than or equal to 8.

Therefore the correct answers are 8 and 9.

dezoksy [38]3 years ago

7 0

Answer:

Step-by-step explanation:

symbolab

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Five less than twice what negative number squared is 157?

fenix001 [56]

Five less than twice what negative number squared is 157 <- put into an expression
-5 + 2(-x^2) = 157
Now simplify:
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4 years ago

8(3 – 2x)+ 4(3x – 2)=-16 <br>Can someone solve for x? please

castortr0y [4]

Answer: x = 8

Step-by-step explanation:

8(3-2x) + 4(3x - 2) = -16

expanding the equation , we have

24 - 16x +12x - 8 = -16

16 - 4x = -16

collecting the like terms

4x = 32