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3 years ago

Which values are solutions to the inequality? 2r≤3r−8 Select each correct answer. 6 7 8 9

Mathematics

2 answers:

Artyom0805 [142]3 years ago

8 0

Answer:

The correct answers are 8 and 9.

Step-by-step explanation:

To solve an inequality you have to solve it like an equality, but when you obtain the solution you don´t have only one value but a set of values that fit into the solution, in this case, the solution to the inequality is:

$2r\leq 3r-8\\2r+8\leq3r\\8\leq3r-2r\\8\leq r$

The set of values found for the solution of this inequality indicates that r takes values greater than or equal to 8.

Therefore the correct answers are 8 and 9.

dezoksy [38]3 years ago

7 0

Answer:

Step-by-step explanation:

symbolab

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3 years ago

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Anna71 [15]

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Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

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3 years ago

Which values are solutions to the inequality? ​ ​2r≤3r−8​ ​ Select each correct answer. 6 7 8 9

Which values are solutions to the inequality? 2r≤3r−8 Select each correct answer. 6 7 8 9