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nadya68 [22]
3 years ago
5

Distance is a vector quantity ... true or false

Physics
2 answers:
Elena-2011 [213]3 years ago
7 0
Answer:False
Reason:
IgorC [24]3 years ago
5 0

Answer:

False

Explanation:

Distance is a sclalar quantity as it has only magnitude and no dirction.

Vector quantities have both magnificent and direction.

HOPE IT HELPS....

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Select the appropriate shape for the given volume form
vredina [299]
Fist one is a cylinder
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the third is a rectangular prism
and the last is the same as the first, a cylinder
3 0
2 years ago
You are rolling on a skateboard with a constant velocity of 12 m/s. As you are moving you toss a baseball straight up into the a
Aliun [14]
Ick! Word problems! They suck. Okay so first of all you want to narrow it dow the equation.


Step 1. What are the numbers? (In this case 12 m/s and 25 m/s)

Step 2. Are you multiplying, dividing? (In this case your dividing)

Step 3. Divide.

I hope that helps.
5 0
3 years ago
While running, a person dissipates about 0.60 J of mechanical energy per step per kilogram of body mass. If a 68 kg person devel
Tresset [83]

Answer:

Speed = 2.25 m/s

Explanation:

(Assume a running step is 1.5 m long)

Given the following data;

Energy = 0.6J

Power = 61 Watts

Mass = 68 kg

To find how fast the person running;

First of all, we would determine the total mechanical energy being dissipated by the person.

Total energy = 0.6 * 68

Total energy = 40.8 Joules

Next, we find the time;

Energy = power * time

40.8 = 61 * time

Time = 61/40.8

Time = 1.5 seconds

Finally, to find the speed;

Speed = distance/time

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Speed = 2.25 m/s

4 0
3 years ago
Help me with the following problem
Snezhnost [94]

The electric field at arbitrary point outside the sphere is determined as the E = σr³/k.

<h3>Electric field determined from Gauss law</h3>

The electric field of the surface is determined from Gauss law as shown below;

E ∫ds = Q/ε

E (4πr²) = Q/ε

E = Q/4πεr² . r

E = \frac{Q R}{4\pi \varepsilon r^3}

<h3>Electric field outside the sphere with dielectric with polarization</h3>

P = \frac{\sigma}{E} \\\\E = \frac{\sigma}{P}

E = \frac{\sigma}{k/r^3} \\\\E = \frac{\sigma r^3}{k}

where;

  • σ is dipole moment of atom of the metal
  • k is dielectric constant

Thus, the electric field at arbitrary point outside the sphere is determined as the E = σr³/k.

The complete question:

A metal sphere of radius R carries a total charge Q. outside the sphere is a dielectric with polarization p(f) k/r^3er. Determine the electric field at arbitrary point outside the sphere.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

6 0
2 years ago
Что означет точки росы 5 C
SCORPION-xisa [38]

Answer:

what is this language

Explanation:

could you maybe mark me brainaist

7 0
3 years ago
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