Question

You throw a water balloon straight up with velocity of 12 m/s. What is it's maximum height?

Answer 1

H=u^2/2g
=12^2/2(10)
=144/20
7.2m

Answer 2

Answer:

Maximum height, h = 7.2 meters

Explanation:

It is given that,

Initial velocity of the balloon, u = 12 m/s

At maximum its final velocity, v = 0

We have to find its maximum height. Let its maximum height is h. Using third equation of motion as :

$v^2-u^2=2ah$

here a = -g

So, $h=\dfrac{v^2-u^2}{-2g}$

$h=\dfrac{-(12\ m/s)^2}{-2\times 10\ m/s^2}$

h = 7.2 meters

Hence, the maximum height of balloon is 7.2 meters.