Which of the following is not used in calculating acceleration?
1 answer:
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Answer:
a) v=2.743m/s
b)
c) T=2.543N
Explanation:
First, calculate the height of the ball at the starting point:
At this point, just in the moment the ball is released, all the energy of the system is potencial gravitational energy. When it is at the bottom all the potencial energy is transformed into kinetic energy:
Solving for v:
if h is the height loss: (l-y')
v=2.743m/s
The centripetal acceleration is the acceleration caused by the tension force exercised by the string, and is pointing outside of the trayectory path (at the lowest point, directly dawn):
To calculate tension, just make the free body diagram of forces in the ball, noticing the existence of the centripetal acceleration: