To solve this problem we will apply the concepts related to the centripetal Force and the Force given by weight and formulated in Newton's second law. Through the two expressions we can find the radius of curve made in the hand. To calculate the normal force, we will include the concepts of sum of forces to obtain the net force on the body at the top and bottom of the maneuver. The expression for centripetal force acting on the jet is

According to Newton's second law, the net force acting on the jet is
F = ma
Here,
m = mass
a = acceleration
v = Velocity
r = Radius
PART A ) Equating the above two expression the equation for radius is


Replacing with our values we have that
![r = \frac{(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{7(9.8m/s^2)}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B%281140km%2Fhr%5B%5Cfrac%7B1000m%7D%7B1km%7D%5Cfrac%7B1hour%7D%7B3600s%7D%5D%29%5E2%7D%7B7%289.8m%2Fs%5E2%29%7D)

PART B )
<u>- The expression for effective weight of the pilot at the bottom of the circle is</u>

![N = (69kg)(9.8m/s^2)+\frac{(69)(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{1.462*10^3m}](https://tex.z-dn.net/?f=N%20%3D%20%2869kg%29%289.8m%2Fs%5E2%29%2B%5Cfrac%7B%2869%29%281140km%2Fhr%5B%5Cfrac%7B1000m%7D%7B1km%7D%5Cfrac%7B1hour%7D%7B3600s%7D%5D%29%5E2%7D%7B1.462%2A10%5E3m%7D)

<em>Note that the normal reaction N is directed upwards and gravitational force mg is directed downwards. At the bottom of the circle, the centripetal force is directed upwards. So the centripetal force is obtained from the gravitational force and the normal reaction. </em>
<u>- The expression for effective weight of the pilot at the top of the circle is</u>

![N = (69kg)(9.8m/s^2)-\frac{(69)(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{1.462*10^3m}](https://tex.z-dn.net/?f=N%20%3D%20%2869kg%29%289.8m%2Fs%5E2%29-%5Cfrac%7B%2869%29%281140km%2Fhr%5B%5Cfrac%7B1000m%7D%7B1km%7D%5Cfrac%7B1hour%7D%7B3600s%7D%5D%29%5E2%7D%7B1.462%2A10%5E3m%7D)

<em>Note that at the top of the circle the centripetal force is directed downwards. So the centripetal force is obtained from normal reaction and the gravitational force. </em>
Answer:
v = 15 m / s
Explanation:
In this exercise we are given the position function
x = 5 t²
and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval
let's look for the displacements
t = 0 x₀ = 0 m
t = 3
= 5 3 2
x_{f} = 45 m
we substitute

v = 15 m / s
Answer:
He should stand from the center of laser pointed on the wall at 1.3 m.
Explanation:
Given that,
Wave length = 650 nm
Distance =10 m
Double slit separation d = 5 μm
We need to find the position of fringe
Using formula of distance



Put the value into the formula


Hence, He should stand from the center of laser pointed on the wall at 1.3 m.
Answer:
It is an example of negative feedback mechanism
Explanation:
Negative feedback mechanism is the process by which the output of a system, process or mechanism is fed back into the input in order to reduce the error in the system.
In the system described in this question, the reabsorption of water is the output, a feedback signal is sent to the control center, which is the input in order to control the release of the hormone responsible for reabsorption of water into the blood.
Answer:
no:
Explanation:
it would grow and no longer be able to fit through the loop due to the hot air expanding.