Answer:
The new function is 
, where x ≠ 5
Step-by-step explanation:
The reciprocal parent function is 
, where x ≠ 0
The translation of f(x) to the right h units is f(x - h)
The translation of f(x) up k units is f(x) + k
The translation of f(x) to the right h units and up k units is f(x - h) + k
∵ The equation of the reciprocal parent function is 
∵ The function is translated 5 units right
∴ h = 5
- That means 5 is subtracted from x ⇒ (x - 5)
∵ The function is translated 3 units up
∴ k = 3
- That means y added by 3
∴
The new function is , where x ≠ 5
Step-by-step explanation:
area of square = 1
area of a circle in square =
bu estimate ![p^ = X/n = 760/1000 = 0.76Therefore, [tex]\frac{\pi }{4} \approx 0.76](https://tex.z-dn.net/?f=p%5E%20%3D%20X%2Fn%20%3D%20760%2F1000%20%3D%200.76%3C%2Fp%3E%3Cp%3ETherefore%2C%20%3C%2Fp%3E%3Cp%3E%0A%5Btex%5D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20%5Capprox%200.76)
b) if n tend to infinity
One nice thing about this situation is that you’ve been given everything in the same base. To review a little on the laws of exponents, when you have two exponents with the same base being:
– Multiplied: Add their exponents
– Divided: Subtract their exponents
We can see that in both the numerator and denominator we have exponents *multiplied* together, and the product in the numerator is being *divided* by the product in the detonator, so that translates to *summing the exponents on the top and bottom and then finding their difference*. Let’s throw away the twos for a moment and just focus on the exponents. We have
[11/2 + (-7) + (-5)] - [3 + 1/2 + (-10)]
For convenience’s sake, I’m going to turn 11/2 into the mixed number 5 1/2. Summing the terms in the first brackets gives us
5 1/2 + (-7) + (-5) = - 1 1/2 + (-5) = -6 1/2
And summing the terms in the second:
3 + 1/2 + (-10) = 3 1/2 + (-10) = -6 1/2
Putting those both into our first question gives us -6 1/2 - (-6 1/2), which is 0, since any number minus itself gives us 0.
Now we can bring the 2 back into the mix. The 0 we found is the exponent the 2 is being raised to, so our answer is
2^0, which is just 1.
Answer:
ok so first we need to find the area of the circle inside which is a=Pi*raduis^2
a=pi*1(radius is half of diamater)
a=3.14
ok then the area of the sqare including the circle is 16 so
16-3.14=12.86
this is is aprox since the area of pi is infinite and i just used 3.14
Hope This Helps!!!
