The simplified form of 3 over 2x plus 5 + 21 over 8 x squared plus 26x plus 15 is <span>6 over the quantity 4 x plus 3.
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The solution would
be like this for this specific problem:
( 3 /( 2x+5 )) + ( 21 / (8x^2 + 26x + 15))
= ( 3 /( 2x+5 )) + ( 21 / (8x^2 + 20x + 6x + 15))
= ( 3 /( 2x+5 )) + ( 21 / (4x(2x + 5) + 3(2x + 5))
= ( 3 /( 2x+5 )) + ( 21 /(2x + 5)(4x + 3)
= [ 3 (4x + 3) + 21 ] /(2x + 5)(4x + 3)
= [ 12x + 9 + 21 ] /(2x + 5)(4x + 3)
= [ 12x + 30 ] /(2x + 5)(4x + 3)
= 6(2x + 5) /(2x + 5)(4x + 3)
= 6 / (4x + 3)
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this answer has satisfied your query and it will be able to help you in your
endeavor, and if you would like, feel free to ask another question.</span>
Answer:
The company should guarantee a lifetime of less than equal to 20.95 years so that less than 3% of the television sets fail while under warranty.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 36 years
Standard Deviation, σ = 8 years
We are given that the distribution of life of television sets is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.03.
Calculation the value from standard normal z table, we have,
Thus, the company should guarantee a lifetime of less than or equal to 20.95 years so that less than 3% of the television sets fail while under warranty.
Answer:
30:48
Step-by-step explanation:
because there are 30 oranges and 48 plums. I got this by putting oranges in front of plums to get the ratio of 30:48
For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5