We can use the fact that a cyclic quadrilateral (i.e. a quadrilateral inscribed in a circle) has the opposite angles supplementary, therefore 2x+(2x+4) = 180 Solving for x: 4x+4=180 4x=180-4=176 x=176/4=44 ° => angle O = 2x = 88 ° angle Q=180-O=180-88 = 92 °