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Stella [2.4K]
3 years ago
11

If a 0.614 g sample of a gas maintains a pressure of 238 mm hg when contained in a 1.0 l flask at 0.0°c, what is the gas's molec

ular weight?
Chemistry
1 answer:
Vadim26 [7]3 years ago
7 0
To determine the molecular weight, we need an equation to relate the molecular weight and the given conditons in the problem statement. Molecular weight is the mass of the mass per one mole of it. For a gas, we can assume ideal gas and use the equation PV=nRT. We need to determine the number of moles present of the gas molecules. We do as follows:

PV = nRT
     n = M / MW
PV = (M/MW) RT
MW = MRT / PV
MW = (0.614 g) ( 0.08205 L - atm / mol - K) ( 273.15 K ) / (238 / 760 atm) ( 1.0 L )
MW = 43.94 g / mol

Therefore, the molecular weight of the gas is 43.94 g/mol.
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Without using Appendix B, predict the sign of ΔS° for(b) KBr(s)→ KBr(aq)
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Since the sign is positive, the entropy increased by 88.48 J/K.

Examine the phases of the species present to determine whether a physical or chemical process will cause an increase or decrease in entropy. Keep in mind "Silly Little Goats" to aid you in telling.

[1 Sf K+1 + 1 Sf Br-1 (aq)] ([1Sf(KBr (s))])

[1(102.5) + 1(82.42)] - [1(96.44)] = 88.48 J/K

If the entropy has grown, we say that Delta S is positive, and if it has dropped, we say that Delta S is negative. Due to its ionic nature, KBr is soluble in water and causes the 'K(+)' ions to hydrate.

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8 0
2 years ago
If 12.4 mol of Ne gas occupies 122.8 L, how many mol of Ne would occupy 339.2 L under the same temperature and pressure? Record
8090 [49]

Answer:

3.43×10¹ mol

Explanation:

Given data:

Initial number of  moles = 12.4 mol

Initial volume = 122.8 L

Final number of moles = ?

Final volume = 339.2 L

Solution:

The number of moles and volume are directly proportional to each other at same temperature and pressure.

V₁/n₁  =  V₂/n₂

122.8 L/ 12.4 mol  =  339.2 L / n₂

n₂ = 339.2 L× 12.4 mol  / 122.8 L

n₂ = 4206.08 L.mol /122.8 L

n₂ = 34.3mol

In scientific notation:

3.43×10¹ mol

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3 years ago
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E=MC(delta)T
=20.0g x 9.00J/g x (94.4-22.8) C
= 12,924.0 J
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Answer:

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What would happen if the number of protons were to change in an atom?
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Answer: you will change the atom from one element to a different element. Sometimes, when you add a proton to an element, the element will become radioactive. If you change the number of neutrons in an atom, you get an isotope of the same element.

Explanation:

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3 years ago
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