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coldgirl [10]
3 years ago
5

How do catalysts increase the rate of a chemical reaction?

Chemistry
1 answer:
kramer3 years ago
4 0
<span>They lower the activation energy.</span>
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Someone who’s good with science this is for you btw I’ll brainlist and rate 5 star due today.
alekssr [168]

Answer:

Solid Osmium transition metal reacts with Oxygen gas to produce solid Osmium tetroxide.

Os(s) + 2O₂(g) -> OsO₄(s)

Explanation:

Osmium tetroxide is another way of writing Osmium (VIII) oxide.

Leaving powdered osmium exposed to air in a room will slowly create osmium tetroxide at room temperature.

Similarly, osmium tetroxide vapor will readily be released from a liquid solution at room temperature.

7 0
2 years ago
Question 7
Svet_ta [14]

Answer:

Check if the ions of two compounds exchange places.

Explanation:

The definition of single replacement is a reaction when an ion replaces another ion, thus the name.

7 0
3 years ago
Read 2 more answers
Calculate the volume occupied by 272g
cupoosta [38]

The answer for the following problem is mentioned below.

<u><em>Therefore volume occupied by methane gas is  184.78 × 10^-3 liters </em></u>

Explanation:

Given:

mass of methane(CH_{4}) = 272 grams

pressure (P) = 250 k Pa =250×10^3 Pa

temperature(t) = 54°C =54 + 273 = 327 K

Also given:

R = 8.31JK-1 mol-1 ,

Molar mass of  methane(CH_{4}) = 16.0​  grams

We know;

According to the ideal gas equation,

<u><em>P × V = n × R × T</em></u>

here,

n = m÷M

n =272 ÷ 16

<u><em>n = 17 moles</em></u>

Therefore,

250×10^3 × V = 17 × 8.31 × 327

V = ( 17 × 8.31 × 327 ) ÷ ( 250×10^3 )

V = 184.78 × 10^-3 liters

<u><em>Therefore volume occupied by methane gas is  184.78 × 10^-3 liters </em></u>

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6 0
2 years ago
The enthalpies of formation of the compounds in the combustion of methane, , are CH4 (g): Hf = –74.6 kJ/mol; CO2 (g): Hf = –393.
algol [13]

Answer:

The amount of energy released from the combustion of 2 moles of methae is 1,605.08 kJ/mol

Explanation:

The chemical reaction of the combustion of methane is given as follows;

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (g)

Hence, 1 mole of methane combines with 2 moles of oxygen gas to form 1 mole of carbon dioxide and 2 moles of water vapor

Where:

CH₄ (g): Hf = -74.6 kJ/mol

CO₂ (g): Hf = -393.5 kJ/mol

H₂O (g): Hf = -241.82 kJ/mol

Therefore, the combustion of 1 mole of methane releases;

-393.5 kJ/mol × 1 + 241.82 kJ/mol × 2 + 74.6 kJ/mol = -802.54 kJ/mol

Hence the combustion of 2 moles of methae will rellease;

2 × -802.54 kJ/mol or 1,605.08 kJ/mol.

8 0
3 years ago
Read 2 more answers
Developing Mastery
Fudgin [204]
The physical state, or phase, that has the greatest kinetic energy is gas. In a gas, the molecules are more free to move and they move more rapidly than in the other phases, and it is this motion that constitutes kinetic energy.
8 0
2 years ago
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