Without using Appendix B, predict the sign of ΔS° for(b) KBr(s)→ KBr(aq)
1 answer:
You might be interested in
Answer:
1) Favor formation of reactant
2) Favor formation of product
3) Favor formation of product
4) Favor formation of product
5) Favor formation of product
Explanation:
The reaction is
The reaction is endothermic
1. Adding hydrobromic acid (HBr)
It will increase the amount of bromide ion. Bromide ion is one of the product so it will favor formation of reactant.
2. Lowering the concentration of bromide (Br-) ions
As we are decreasing the the concentration of product it will favor formation of more products
3. Heating the concentrations
If we are heating the mixture, it will increase the temperature and it will favor endothermic reaction. Thus will favor formation of product.
4. Adding solid silver bromide (AgBr)
If we are adding silver bromide it means we are increasing the concentration of reactant, it will favor formation of products
5. Removing silver (Ag+) ions
Removing silver ions means we are decreasing the concentration of product thus it will favor formation of products.
Answer:
a.
b.
Explanation:
a. First, we solve the specific heat equation as follows:
b. Then, we use the molar mass of titanium to determine its molar heat capacity, as follows: