Answer:
0.4550
Explanation:
In this example, R allele is dominant, so individuals RR and Rr can roll their tongues. If in a population of 1000 gorillas, there are 575 gorillas who can roll their tongues, they will be RR and Rr.
In this case, there is Hardy Weinberg Equilibrium, so the following will be true:
Where:
frequency of RR
frequency of Rr
frequency of rr
The question is what is the frequency of heterozygotes, or, what is the value of 2pq.
We know that RR+Rr is 575 individuals in a population of 1000, or 0.575.
In other words:
So, it is possible to find :
Now, there are two alleles in the population, so the following will be true:
It is possible to find q (the frequency of allele r) and p (the frequency of allele p):
Therefore:
Now, the frequency of heterozygotes or 2pq is:
Answer:
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This means that if you pick 100 Hawaians randomly, the fraction of them having blood type AB will be close to 1/100. Probability is a statistical term describing the likelihood that an event will occur, in this case, the likelihood of a native Hawaian having an AB blood type. 1 in 100 means that out of 100 people randomly chosen the amount of them having this blood type will be very close to 1. Since the sample population is randomly chosen, it can not be certain that only 1 out of 100 will have this blood type.
Answer:
A) stroma of the chloroplast.
Explanation:
The light independent reactions take place in the stroma of the the chloroplast.
Answer:
The Answer is: pyruvate oxidation
Explanation:
In prokaryotes, it happens in the cytoplasm. Overall, pyruvate oxidation converts pyruvate—a three-carbon molecule—into acetyl CoAstart text, C, o, A, end text—a two-carbon molecule attached to Coenzyme A—producing an NADHstart text, N, A, D, H, end text and releasing one carbon dioxide molecule in the process.