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3 years ago

If anyone can help with this pls do! i need to get this right thank u!

Mathematics

2 answers:

anygoal [31]3 years ago

5 0

50a + 20w is greater than or equal to 350

nika2105 [10]3 years ago

3 0

50a+20w≥350

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the centers of Marathon County Bayfield County and Dodge County all lie along a straight line if Marathon County is equidistant

Evgen [1.6K]

Marathon C is in the middle.

From Marathon C to Dodge C is 487

Then From Marathon C to Bayfield C is also 487

And from Dodge C to Bayfield C is 487 + 487 = 974 miles

5 0

3 years ago

Simplify -3x+1y+8x-8y

Fudgin [204]

Answer:

-3x +1y +8x -8y

=5x-7y

The answer is: 5x-7y

6 0

3 years ago

Read 2 more answers

Write the integral that gives the length of the curve y = f (x) = ∫0 to 4.5x sin t dt on the interval [0,π].

Troyanec [42]

Answer:

Arc length $=\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

Arc length $=9.75053$

Step-by-step explanation:

The arc length of the curve is given by $\int_a^b \sqrt{1+[f'(x)]^2}\ dx$

Here, $f(x)=\int_0^{4.5x}sin(t) \ dt$ interval $[0, \pi]$

Now, $f'(x)=\frac{\mathrm{d} }{\mathrm{d} x} \int_0^{4.5x}sin(t) \ dt$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( [-cos(t)]_0^{4.5x} \right )$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( -cos(4.5x)+1 \right )$

$f'(x)=4.5sin(4.5x)$

Now, the arc length is $\int_0^{\pi} \sqrt{1+[f'(x)]^2}\ dx$

$\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

After solving, Arc length $=9.75053$

5 0

3 years ago

in preparation for a party, brant is putting desserts onto platters. the chocolate cake is cut into 15 pieces and the cheesecake

marishachu [46]

Answer:

The greatest number of platters he can prepare is 3.

Step-by-step explanation:

Given : In preparation for a party, brant is putting desserts onto platters. the chocolate cake is cut into 15 pieces and the cheesecake is cut into 6 pieces. if he wants to prepare identical platters without having any cake left over.

To find : What is the greatest number of platters he can prepare?

Solution :

The greatest number of platters he can prepare is given by finding the GCF of 15 and 6.

Factoring the numbers,

$6=2\times 3$