2x+8=3kx (3k-2)x+8=0
3x-kx=2. (3-k)x-2=0
3k-2)x+10=3-k)x
4k-5=10/x
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3x-y-2=2x+8-3y
X+2y-10=0
X+2kx-10=0
K=(10-x)/2x
Answer:
6/(49π) ≈ 0.03898 m/min
Step-by-step explanation:
V = πr²h . . . . formula for the volume of a cylinder
dV/dt = πr²·dh/dt . . . . differentiate to find rate of change
Solving for dh/dt and filling in the numbers, we have ...
dh/dt = (dV/dt)/(πr²) = (6 m³/min)/(π(7 m)²) = 6/(49π) m/min
dh/dt ≈ 0.03898 m/min
Answer:
3
Step-by-step explanation:
- 4x³y² + 6
the x is raised to the power of 3 , that is exponent of x is 3
Answer: 8, 9, and 10
Step-by-step explanation: whatever value m is must be less than 18