Answer:
Step-by-step explanation:
This is already factored for us, which is really nice, so now all we need to do is apply the Zero Product Property to the sets of parenthesis and solve for x, which will give us the 2 times that the object is on the ground.
x + 1 = 0 so
x = -1
x - 9 = 0 so
x = 9
We all know that time cannot ever be negative, so the time that the object is on the ground is 9 seconds after it's launched (which was from an initial height of 45 meters).
Z=22
180-120=60
2x+16=60
2x=44
Z=22
We are given the height of Joe which is 1.6 meters, the length of his shadow is 2 meters when he stands 3 meters from the base of the floodlight.
First, we have to illustrate the problem. Then we can observe two right triangles formed, one is using Joe and the length of the shadow, the other is the floodlight and the sum of the distance from the base plus the length of the shadow. To determine the height of the floodlight, use ratio and proportion:
1.6 / 2 = x / (2 +3)
where x is the height of the flood light
solve for x, x = 4. Therefore, the height of the floodlight is 4 meters.
The answer is 22.8
Cos 64 = adj./hypotenuse
Cos64=10/x
X(cos64)=10
X= 10/cos64
= 22.8
