We need to see the table in order to answer the question...
The initial statement is: QS = SU (1)
QR = TU (2)
We have to probe that: RS = ST
Take the expression (1): QS = SU
We multiply both sides by R (QS)R = (SU)R
But (QS)R = S(QR) Then: S(QR) = (SU)R (3)
From the expression (2): QR = TU. Then, substituting it in to expression (3):
S(TU) = (SU)R (4)
But S(TU) = (ST)U and (SU)R = (RS)U
Then, the expression (4) can be re-written as:
(ST)U = (RS)U
Eliminating U from both sides you have: (ST) = (RS) The proof is done.
Answer:
use formula of equilateral triangle = roots 3/4 a square.
The answers would be 24 and 52 hope this helped!
Answer:
No solution
Step-by-step explanation:
The given equations are :
9x-3y=-6
3x-y=2.....(1)
5y=15x+10
5y-15x=10
or
y-3x=2 .....(2)
Equations (1) and (2) shows that the lines are parallel. We know that for parallel lines, there is no solution.
