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Jlenok [28]
3 years ago
15

You are making gift baskets. each basket will contain three different types of candles: tapers, pillars ad jar candles. tapers c

ost $1 each, pillars cost $4 each, and jar candles cost $6 each. you put 8 candles costing a total of $24 in each basket, and you include as many tapers as pillars and jar candles combined. how many of each type of candle will be in a basket?
Mathematics
1 answer:
nikdorinn [45]3 years ago
4 0
Let
x = the number of tapers (each coss $1)
y = the number of pillars (each costs $4)
z = the number of jars (each costs $6)

There are 8 candles in each basket, therefore
x + y + z = 8                   (1)

The cost per basket is $24, therefore
x + 4y + 6z = 24             (2)

The number of tapers equals the sum of pillars and jars, therefore
x = y + z                          (3)

Substitute (3) into (1) and into (2).
y + z + y + z = 8
2y + 2z = 8
y + z = 4                           (4)

y + z + 4y + 6z = 24
5y + 7z = 24                     (5)
From (4), y = 4 -z. Substitute into (5).
5(4 - z) + 7z = 24
2z + 20 = 24
2z = 4
z = 2
y = 4 - z = 4 - 2 = 2
x = y + z = 2 + 2 = 4

Answer: 4 tapers, 2 pillars, 2 jars.
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Find x- and y-intercepts. Write ordered pairs representing the points where the line crosses the axes. 2x+3y=6
sweet-ann [11.9K]

Answer:

x-intercept: (3, 0)

y-intercept: (0, 2)

Step-by-step explanation:

For a function like:

y = f(x)

The x-intercept is the value of x when y = 0

the y-intercept is the value of y when x = 0

Also remember that an ordered pair is written as (x, y).

In this case we have the equation:

2*x + 3*y = 6

For the x-intercept, we just replace y by zero in the equation, then we get:

2*x + 3*0 = 6

Solving this for x, we get:

2*x = 6

x = 6/2 = 3

Then in this case, the ordered pair for the x-intercept is (3, 0)

For the y-intercept, we just need to replace x by zero in the equation:

2*0 + 3*y = 6

Solving this for y, we get:

3*y = 6

y = 6/3 = 2

Then the ordered pair for the y-intercept is (0, 2)

8 0
3 years ago
2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books
insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

  • When the books are arranged in any order, the number of arrangements is 3628800
  • When the mathematics book must not be together, the number of arrangements is 2903040
  • When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
  • When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

\mathbf{Novels = 3}

\mathbf{Mathematics = 2}

\mathbf{Chemistry = 5}

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

\mathbf{n = Novels + Mathematics + Chemistry}

\mathbf{n = 3 + 2 +  5}

\mathbf{n = 10}

The number of arrangement is n!:

So, we have:

\mathbf{n! = 10!}

\mathbf{n! = 3628800}

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

\mathbf{Maths\ together = 2 \times 9!}

Using the complement rule, we have:

\mathbf{Maths\ not\ together = Total - Maths\ together}

This gives

\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}

\mathbf{Maths\ not\ together = 2903040}

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

\mathbf{Novels = 3}

\mathbf{Chemistry = 5}

First, arrange the novels in:

\mathbf{Novels = 3!\ ways}

Next, arrange the chemistry books in:

\mathbf{Chemistry = 5!\ ways}

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

\mathbf{n =Mathematics + 1 + 1}

\mathbf{n =2 + 1 + 1}

\mathbf{n =4}

So, the number of arrangements is:

\mathbf{Arrangements = n! \times 3! \times 5!}

\mathbf{Arrangements = 4! \times 3! \times 5!}

\mathbf{Arrangements = 17280}

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

\mathbf{Mathematics = 2}

\mathbf{Novels = 3}

\mathbf{Chemistry = 5}

First, arrange the mathematics in:

\mathbf{Mathematics = 2!}

Literally, the number of chemistry and mathematics now is:

\mathbf{n =Chemistry + 1}

\mathbf{n =5 + 1}

\mathbf{n =6}

So, the number of arrangements of these books is:

\mathbf{Arrangements = n! \times 2!}

\mathbf{Arrangements = 6! \times 2!}

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

\mathbf{Arrangements = ^7P_3}

So, the total arrangement is:

\mathbf{Total = 6! \times 2!\times ^7P_3}

\mathbf{Total = 6! \times 2!\times 210}

\mathbf{Total = 302400}

Read more about permutations at:

brainly.com/question/1216161

8 0
2 years ago
the area of a rectangle is 10 square units the length is 2 units and the width is y units 10 = 2y what is the value of y. y = 12
frutty [35]

Answer:

2(5+y)+2y=38 10+2y+2y=38 4y=28 y=7  i think

Step-by-step explanation:

4 0
3 years ago
Use synthetic division to divide (x3 + 12x2 + 38x + 26) ÷ (x + 4)
KengaRu [80]
Divisor is -4
Use coefficients 1    12    38    26

Bring down 1 multiply by -4 and add to 12 =8
Multiply 8 by -4 and add to 38 = 6 
Multiply 6 by -4 and add to 26 = 2 which is the remainder

looks like     1    12    38    26
                          -4   -32   -24
                    ________________
                     1     8      6     R 2
so answer A of x squared + 8x + 6 +R2 is correct
5 0
3 years ago
Read 2 more answers
What is the standard form of (2-4i)(3+51)/(3+i)
garri49 [273]
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6 0
3 years ago
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