Answer:
3.6 x 4.639 + 5.831 = 2000
Explanation:
In this problem, we need to find the value of 3.6 x 4.639 + 5.831.
Here, 3.6 has 2, 4.639 and 5.831 has 4 significant figures.
We can use BODMAS RULE to find it as follows :
3.6 x 4.639 + 5.831 = (3.6 x 4.639) + 5.831
= 2325.96 + 5.831
in significant gigure,
= 2300 + 5.831
= 2305.831
In one significant figure,
= 2000
Hence, the answer of the problem is 2000.
Earth's atmosphere is 78% nitrogen, 21% oxygen, 0.9% argon, and 0.03% carbon dioxide with very small percentages of other elements. Our atmosphere also contains water vapor.
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To solve this problem, we begin by first calculating the area of the front lawn. The length and width of the lawn was given and the area of a rectangle is given by the formula: Area = length x width. Thus, the area of the front lawn can be obtained by multiplying 18 ft by 20 ft, wherein we get 360 ft^2 as the area.
Second, the problem indicated that each square foot of lawn accumulates 1450 new snow flakes per minute. This can be translated into the expression 1450 snow flakes/ (minute·ft^2). In this way, we can convert it to units of mass (kg). Afterwards, we simply need to multiply it to the area of the lawn and convert minute to hour. The following expression is then used:
1450 snow flakes/ (minute·ft^2) x 1.90 mg/snow flake x 1 g/1000 mg x 1kg/1000 g x 360 ft^2 x 60 minutes/hour = 59.508 kg snow flake/hour
It is then calculated that 59.508 kg of snow flake accumulates in the lawn every hour.
<span>Dominant traits are traits that will be expressed. Recessive traits are traits that are never expressed in the presence of a dominant trait. They can only be expressed when both alleles are recessive.
This is true.
Dominant traits are just that - dominant. If they are present in the genotype, they will appear in the phenotype.</span>