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stiks02 [169]
3 years ago
10

Cual es la diferencia entre un volcán de verdad y uno hecho casero

Chemistry
1 answer:
ella [17]3 years ago
5 0
La diferensia es que los volcanes caseros no existen solo existen los verdaderos
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Which of these statements is false? (A) Acetylene (ethyne) can be converted to the acetylide anion by treating with a strong bas
Free_Kalibri [48]

Answer:

(C) Acetylene (ethyne) can be converted to the acetylide anion by treating with a strong base such as CH₃​​Li.

Explanation:

Acetylene (C₂H₂) can be converted to the acetylide anion (C₂⁻²) when treated with a base because it will donate protons (2H⁺). So it will be a neutralization reaction. NaNH₂ and NaOH are strong bases because they are good electrons donators ( NaNH₂ has pair of electrons on N, and NaOH has the group OH⁻), but CH₃Li has no pair of electrons to donate, so it's not a strong base.

4 0
4 years ago
Give me a statement regarding the process of science discovery and development of atomic theory
matrenka [14]
Can you say please? Just kidding!
The process of science discovery depends upon changing your theories based upons new evidence from new experiments.  New technology allows for new experiments, leading to new theories.  
5 0
3 years ago
Convert 1176 mmHg to kPa
OLEGan [10]

Answer:

 156.8kPa

Explanation:

The problem here is to convert mmHg to kPa;

We have been given:

            1176mmHg and the problem is to convert to kPa;

  1000Pa = 1kPa

               1 mmHg  =  133.322Pa

               1176mmHg will give  1176 x 133.322  = 156787.1Pa

To kPa;

             156.8kPa

8 0
3 years ago
An electron in the hydrogen atom makes a transition from an energy state of principal quantum number ni to the n = 2 state. If t
topjm [15]

Answer:

\boxed{3}

Explanation:

The Rydberg equation gives the wavelength λ for the transitions:

\dfrac{1}{\lambda} = R \left ( \dfrac{1}{n_{i}^{2}} - \dfrac{1}{n_{f}^{2}} \right )

where

R= the Rydberg constant (1.0974 ×10⁷ m⁻¹) and

\text{$n_{i}$ and $n_{f}$ are the numbers of the energy levels}

Data:

n_{f} = 2

λ = 657 nm

Calculation:  

\begin{array}{rcl}\dfrac{1}{657 \times 10^{-9}} & = & 1.0974 \times 10^{7}\left ( \dfrac{1}{2^{2}} - \dfrac{1}{n_{f}^{2}} \right )\\\\1.522 \times 10^{6} &= &1.0974\times10^{7}\left(\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \right )\\\\0.1387 & = &\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \\\\-0.1113 & = & -\dfrac{1}{n_{f}^{2}} \\\\n_{f}^{2} & = & \dfrac{1}{0.1113}\\\\n_{f}^{2} & = & 8.98\\n_{f} & = & 2.997 \approx \mathbf{3}\\\end{array}\\\text{The value of $n_{i}$ is }\boxed{\mathbf{3}}

7 0
3 years ago
Need help for number 4. do i use the q=mc DELTA T equation or the q=mHfusion?
Natasha2012 [34]
Since it is a phase change, use the mHfusion equation.
7 0
3 years ago
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