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kirill115 [55]
3 years ago
6

Plz help with number 4

Chemistry
1 answer:
In-s [12.5K]3 years ago
6 0
Extensive: mass, length, volume
Inexpensive: color, density, aluminum
You might be interested in
Hi All,
Novosadov [1.4K]

Answer:Combination.

Decomposition.

Single displacement.

Double displacement.

Combustion.

Redox.

Explanation:

4 0
3 years ago
How many molecules of N204 are in 85.0 g of N2O4?
alukav5142 [94]

Answer:

5.56 × 10^23 molecules

Explanation:

The number of molecules in a molecule can be calculated by multiplying the number of moles in that molecule by Avagadro's number (6.02 × 10^23)

Using mole = mass/molar mass

Molar mass of N2O4 = 14(2) + 16(4)

= 28 + 64

= 92g/mol

mole = 85.0/92

= 0.9239

= 0.924mol

number of molecules of N2O4 (nA) = 0.924 × 6.02 × 10^23

= 5.56 × 10^23 molecules

4 0
3 years ago
Which of these correctly lists the stages of development of the inner planets?
ZanzabumX [31]
The correct answer for the question that is being presented above is this one:  "C. planetesimals ® heavier elements ® inner planets ® protoplanets" The list of the stages of development of the inner planets is this <span>C. planetesimals ® heavier elements ® inner planets ® protoplanets</span>
5 0
3 years ago
Read 2 more answers
Which is the best description of the chemical reaction shown here in aqueous solution? ch3ch2cooh (aq) ↔ ch3ch2coo- (aq) + h+ (a
AnnZ [28]
The given reaction: 
<span>ch3ch2cooh (aq) ↔ ch3ch2coo- (aq) + h+ (aq)
is called a reversible reaction.

This means that, the reaction does not reach an end point.
In this type of reactions, reactants react together to form products, while products combine together to form reactants.
So, the reaction proceeds in both direction forming both reactants and products.</span>
6 0
3 years ago
Read 2 more answers
"A crosslinked copolymer consists of 57 wt% ethylene (C2H4) repeat units and 43 wt% propylene (C3H6) repeat units. Determine the
ch4aika [34]

Explanation:

Percentage ethylene by weight = 57%

Percentage propylene by weight = 43%

Suppose in 100 grams of polymer:

Mass of ethylene = 57 g

Mass of propylene = 43 g

Moles of ethylene = \frac{57 g}{28 g/mol}=2.036 mol

Moles of propylene = \frac{43g}{42g/mol}=1.024 mol

1 mole = N_A =6.022\times 10^{23} molecules/ atoms

Units of ethylene = 2.036 mol\times N_A

Units of propylene = 1.024 mol\times N_A

a) Fraction of ethylene units:

=\frac{2.036 mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{509}{765}

b ) Fraction of propylene units:

=\frac{1.024mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{256}{765}

3 0
3 years ago
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