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sp2606 [1]
3 years ago
7

If 8.74 g of CuNO3 is dissolved in water to make a 0.700 M solution, what is the volume of the solution

Chemistry
1 answer:
Bess [88]3 years ago
4 0
Hope this helps you.

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6.
GuDViN [60]

Answer:

A phosphorus atom forms a P3- ion by gaining three electrons.

here

4 0
2 years ago
What is the density of a liquid if it has a mass of 12.9g ?
user100 [1]
Find it on google i’m pretty sure i saw it somewhere so sorry this doesn’t help
4 0
3 years ago
How many molecules of copper sulfate are needed to produce 5.0×1024 molecules of sodium sulfate?
lubasha [3.4K]

Answer:

5.0 × 10²⁴ molecules

Explanation:

Step 1: Write the balanced double displacement reaction

2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂

Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄

We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.

5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol

Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄

The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.

Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄

We will use Avogadro's number.

8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule

4 0
3 years ago
Calculate the number of formula units in 2.50 mol NaNO
marta [7]

The number of formula units in 2.50 mol of the compound is  15.1 * 10^23.

The question is unclear whether NaNO2 or NaNO3 is implied. However,in either case, the solution applies equally.

6.02 * 10^23 formula units of the compound are contained in 1 mole

x formula units are contained in 2.5 moles of the compound

x = 6.02 * 10^23 formula units * 2.5 moles/ 1 mole

x = 15.1 * 10^23 formula units of the compound.

Learn more; brainly.com/question/9743981

3 0
2 years ago
As a scuba diver descends under water, the pressure increases. At a total air pressure of 2.71 atm and a temperature of 25.0 C,
Semenov [28]

Answer:

1.32\times 10^{-3} mol/Lis the solubility of nitrogen gas in a diver's blood.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{N_2}=K_H\times p_{liquid}

where,

K_H = Henry's constant = 6.26 \times 10^{-4}mol/L.atm

p_{N_2} = partial pressure of nitrogen

p_{N_2}= P\times \chi_{N_2} (Raoult's law)

=2.71 atm\times 0.78=2.1138 atm

C_{N_2}=6.26 \times 10^{-4}mol/L.atm\times 2.1138 atm

C_{N_2}=1.32\times 10^{-3} mol/L

1.32\times 10^{-3} mol/Lis the solubility of nitrogen gas in a diver's blood.

3 0
3 years ago
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