Answer:
Completing the square answer

Solution set
= 
Step-by-step explanation:
Assuming the question is correctly interpreted as 2m2 = 2m², here is how to proceed
We have 
Divide by 2 on both sides

Take half of the coefficient of
and square it
![\left[ - \frac{3}{2} \cdot \frac{1}{2} \right]^2 = \frac{9}{16}](https://tex.z-dn.net/?f=%5Cleft%5B%20%20-%20%5Cfrac%7B3%7D%7B2%7D%20%5Ccdot%20%5Cfrac%7B1%7D%7B2%7D%20%5Cright%5D%5E2%20%3D%20%5Cfrac%7B9%7D%7B16%7D)
Add the result to both sides

can be re-written as a perfect square

The RHS becomes

Therefore,

Take the square root of both side
![m - \frac{3}{4} = \pm \sqrt[]{ - \frac{391}{16}}](https://tex.z-dn.net/?f=m%20%20-%20%5Cfrac%7B3%7D%7B4%7D%20%3D%20%5Cpm%20%5Csqrt%5B%5D%7B%20-%20%5Cfrac%7B391%7D%7B16%7D%7D)
Simplify
![m - \frac{3}{4} = \pm \frac{\sqrt[]{391}i}{4}](https://tex.z-dn.net/?f=m%20%20-%20%5Cfrac%7B3%7D%7B4%7D%20%3D%20%5Cpm%20%5Cfrac%7B%5Csqrt%5B%5D%7B391%7Di%7D%7B4%7D)
Adding
both sides
![m = \frac{3}{4} + \frac{\sqrt[]{391}i}{4}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B3%7D%7B4%7D%20%2B%20%5Cfrac%7B%5Csqrt%5B%5D%7B391%7Di%7D%7B4%7D)
This gives the two solutions
and
![m = \frac{3}{4} - \frac{\sqrt[]{391}i}{4}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B3%7D%7B4%7D%20-%20%5Cfrac%7B%5Csqrt%5B%5D%7B391%7Di%7D%7B4%7D)
which becomes
and

Answer:
Part A: if the city is hotter in temperature more people will want some refreshing lemonade.
Part B: Draw the graph then draw a line using the Dots in the graph, it's weak positive btw
Answer:
y = -2x + 7 is the equation if that's what you are asking for.
Factoring by grouping usually pairs up the first 2 sets of expressions with the second 2 sets. Ours looks like this, then:

. If we factor out the common x-squared in the first set of parenthesis, along with factoring out the common 5 in the second set, we get this:

. Now the common expression that can be factored out is the (x-9). When we do that, here's what it looks like:

. I'm not sure how far you are going with this. You could set each of those equal to 0 and solve for x in each case. The first one is easy. If x - 9 = 0, then x = 9. The second one involves the imaginary i since x^2 = -5. In that case,

. Hopefully, in what I have given you, you can find what you're looking for.
Answer:
<h2>2^-2</h2>
Step-by-step explanation:
2^(3-5)
=2^-2