It depends on where you are....
Using it's concept, the range of function g is given by:
B. ![\{y|y \in \mathbb{R}, y \neq -4, -3\}](https://tex.z-dn.net/?f=%5C%7By%7Cy%20%5Cin%20%5Cmathbb%7BR%7D%2C%20y%20%5Cneq%20-4%2C%20-3%5C%7D)
<h3>What is the range of a function?</h3>
The range of a function is the set that contains all possible output values for the function. In a graph, it is the values of y.
In this graph, y assumes all values except y = -3 and y = -4, hence the range is given by:
B. ![\{y|y \in \mathbb{R}, y \neq -4, -3\}](https://tex.z-dn.net/?f=%5C%7By%7Cy%20%5Cin%20%5Cmathbb%7BR%7D%2C%20y%20%5Cneq%20-4%2C%20-3%5C%7D)
More can be learned about the range of a function at brainly.com/question/10891721
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Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
(-1)(-1)(-1)+(-1)=-1-1=-2
-2
Hope this helps!