Answer: $393
Step-by-step explanation: (34’+ 30’+67’) x $3.00 = 131 x 3.00 = 393
Answer:
I think
11cm²-5cm²=121+25
and the square root of that will give you 12.08
and that's the answer
9 - x < 8 => -x < 8 - 9 => -x < -1 => x > 1
9 - x > 3 => -x > 3 -9 => -x > -6 => x < 6
So the number is between 1 and 6, notation 1 < x < 6
Answer:
To get 20 cups of purple paint, the table shows that we need 8 cups of blue paint and 12 cups of red paint. We can solve the problem using double (or triple) number lines.
3.01 m/s
This is a simple projectile calculation. What we want is a vertical velocity such that the time the droplet spends going up and going back down to the surface exactly matches the time the droplet takes to travel horizontally 0.800 meters. The time the droplet spends in the air will is:
V*sqrt(3)/2 ; Vertical velocity.
(V*sqrt(3)/2)/9.8 ; Time until droplet reaches maximum height
(V*sqrt(3))/9.8 ; Double that time for droplet to fall back to the surface.
The droplet's horizontal velocity will be:
V/2.
So the total distance the droplet travels will be:
d = (V*sqrt(3))/9.8 * V/2
d = V^2*sqrt(3)/19.6
Let's substitute the desired distance and solve for V
d = V^2*sqrt(3)/19.6
0.8 = V^2*sqrt(3)/19.6
15.68 = V^2*sqrt(3)
15.68/sqrt(3) = V^2
15.68/1.732050808 = V^2
3.008795809 = V
So after rounding to 3 significant figures, the archerfish needs to spit the water at a velocity of 3.01 m/s
Let's verify that answer.
Vertical velocity: 3.01 * sin(60) = 3.01 * 0.866025404 = 2.606736465
Time of flight = 2.606736465 * 2 / 9.8 = 0.531987034 seconds.
Horizontal velocity: 3.01 * cos(60) = 3.01 * 0.5 =
