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Ivahew [28]
3 years ago
8

Laura's job is 4 1/2 miles away. If she starts walking to her job at 9:00 a.m. and is scheduled to start working at 11:00 a.m.,

will she arrive at her job on time? Explain your reasoning.
Mathematics
1 answer:
irina [24]3 years ago
7 0

Answer:

<u>Laura has to walk at 2 1/4 miles per hour or faster to arrive to her job on time.</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Distance from Laura's home to her job = 4 1/2 miles

Time when Laura starts to walk to her job : 9:00 a.m.

Time when Laura is scheduled to start working : 11:00 a.m.

2.  Will she arrive at her job on time?

Time Laura has to complete the distance from her home to her job = 2 hours (11 -9)

Speed that Laura need to walk to arrive to her job on time = Distance from Laura's home to her job/Time Laura has to complete the distance from her home to her job

Speed that Laura need to walk to arrive to her job on time = 4 1/2 miles/2 hours = (4 1/2)/2 = (9/2)/2 = 9/2 * 1/2 = 9/4 = 2 1/4

Speed that Laura need to walk to arrive to her job on time = 2 1/4 miles per hour.

<u>Laura has to walk at 2 1/4 miles per hour or faster to arrive to her job on time.</u>

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Answer:

m<GFA = 110

Step-by-step explanation:

1. ABCD - parallelogram                          Definition of a parallelogram

                                                                   (AB ll CD) (AD ll BC)

2. m<B + m<C = 180                                    Consectuive angles in a

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3. m<GCB = 1/2 m<C                                  Definition of angles bisector

   m<GCB = 70

4. m<B = m<D = 110                                    Opposite angles in a

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6. m<GCB+m<CDG+m<CGD=180              Sum of anlges in a triangle (ΔCDG)

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   m<CGD = 55

7. m<CGD + m<DGF = 180                            Linear pair, supplmentary angles

  55 + m<DGF = 180

  m<DGF = 125

8. m<C = m<A = 70                                     Opposite angles in a paralellogram

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  m<ADG = 55

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