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Ivahew [28]
3 years ago
8

Laura's job is 4 1/2 miles away. If she starts walking to her job at 9:00 a.m. and is scheduled to start working at 11:00 a.m.,

will she arrive at her job on time? Explain your reasoning.
Mathematics
1 answer:
irina [24]3 years ago
7 0

Answer:

<u>Laura has to walk at 2 1/4 miles per hour or faster to arrive to her job on time.</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Distance from Laura's home to her job = 4 1/2 miles

Time when Laura starts to walk to her job : 9:00 a.m.

Time when Laura is scheduled to start working : 11:00 a.m.

2.  Will she arrive at her job on time?

Time Laura has to complete the distance from her home to her job = 2 hours (11 -9)

Speed that Laura need to walk to arrive to her job on time = Distance from Laura's home to her job/Time Laura has to complete the distance from her home to her job

Speed that Laura need to walk to arrive to her job on time = 4 1/2 miles/2 hours = (4 1/2)/2 = (9/2)/2 = 9/2 * 1/2 = 9/4 = 2 1/4

Speed that Laura need to walk to arrive to her job on time = 2 1/4 miles per hour.

<u>Laura has to walk at 2 1/4 miles per hour or faster to arrive to her job on time.</u>

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The function f(x) = –x2 + 20x – 75 models the profit from one customer, in dollars, a shop makes for printing photos, where x is
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The function is graphed as shown below

Part A:

We use the formula - \frac{b}{2a} to find the vertex of the function. A quadratic function of the form of a x^{2} +bx+c and equating this form to the given function - x^{2} +20x-75, we have
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Substituting a and b into the vertex formula, we have
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This calculation means that the highest profit is achieved when the number of photo printed equals to ten photos

Part B:

We can find solution to this equation by factorising

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4 years ago
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Answer:

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Step-by-step explanation:

According to the Question,

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Hence, the total cost of Roy's ride is 20.5 + 2.55(fixed cost) = $23.05

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