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posledela
3 years ago
9

Express the number in decimal notation. 5.2 �� 104 a. 5200 b. 208 c. 520,000 d. 52,000

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0
5.2×10^4=5.2×10000=52×1000=52000
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Mathswatch Question! Mr Powers checks his electricity bill. Here are his meter readings. New reading: 6538 units, Old reading: 6
Setler79 [48]

Answer:

Cost = 284 x

Step-by-step explanation:

Given

Old = 6245\ units

New = 6538\ units

Required

The cost of units used

First, calculate the number of units used.

Units = New - Old

Units = 6538 - 6254

Units = 284

Next, multiply the units used by the cost per units,

Since the cost per unit is not given, we assume that it is x.

So, the total cost is:

Cost = Units * Cost\ per\ units

Cost = 284 * x

Cost = 284 x

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Where is the opposite of the opposite of -1.9 situated on the number line ​
SashulF [63]

Answer:

B

Step-by-step explanation:

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Name three points in the diagram that are not collinear.
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b

Step-by-step explanation:

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3 years ago
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A snail is at the bottom of a 10 ft wall. Each day it climbs up 3 ft . Each night it slides back down 1 ft. On which day will it
krek1111 [17]
He will reach the wall in

DO IT YOURSELF ANSWER:
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Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-
ivanzaharov [21]

Answer:

c = \displaystyle\frac{9}{4}

Step-by-step explanation:

The following information is missing in the given question:

f(x) = \sqrt{x}

Using this we may solve the question as:

We are given the following in the question:

f(x) = \sqrt{x}, x \in [0,9]

We have to find the number c such that f(x) satisfies the Mean value theorem.

Mean Value theorem:

It states that if the function is differentiable in the closed interval [a,b], differentiable in the interval (a,b), then there exist c in (a,b) such that:

f'(c) = \displaystyle\frac{f(b)-f(a)}{b-a}

Now,

f(x) = \sqrt{x}\\f'(x) = \frac{1}{2\sqrt{x}}

Continuity in [0,9]

Since a polynomial function is continuous everywhere, f(x) is continuous in [0,9]

Differentiability in (0,9)

Since a polynomial function is differentiable everywhere the given function is differentiable in interval (0,9)

Then, by mean value theorem:

f'(c) = \displaystyle\frac{f(b)-f(a)}{b-a}\\\\\frac{1}{2\sqrt{c}} = \frac{f(9) - f(0)}{9-0} = \frac{3}{9}\\\\\frac{1}{2\sqrt{c}} = \frac{1}{3}\\\\c= \frac{9}{4}

7 0
3 years ago
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