33 percent.
7/21 = 0.3333333
Answer:
a) 
b) 
c) 
d) E(3X + 2) = 21.35
e) 
f) V(3X+2) = 140.832
g) E(X+1) = 7.45
h) V(X+1) = 15.648
Step-by-step explanation:
a) 

b)

c)

d)

e)

f)

g)

h)

Answer: The numbers are 10 and 23
Step-by-step explanation:
Let the smaller number be x
And the larger number be y
Ist sentence;
1. The sum of two numbers is 33.
X + y= 33 .........eqn 1
2. second sentence
the larger number is 3 more than two times the smaller number.
Y = 3 +2x
Put y into eqn 1
X+ 3 +2x = 33
3x= 33- 3
3x= 30
X = 30/3
X= 10 and y= 3+ 2x
Y= 3+ 2(10)
Y = 3+ 20
Y= 23
Therefore the two numbers are 10 and 23
Use the distance formula:
<span>

<span>
Plug in the given coordinates:
</span><span>

<span>
Simplify:
</span>




You can leave it as:

or in decimal form as: 7.2
</span></span>
My best answer is B.) 173. 19/25 = ?/227. 25 times 9.08 = 227 so 9.08 times 19 = 172.52 1 which rounds up to 173