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vivado [14]
2 years ago
15

What are the roots of the equation 16x2 – 64x + 65 = 0 in simplest a + bi form?

Mathematics
1 answer:
Semenov [28]2 years ago
8 0

Step-by-step explanation:

16 \times 2 - 64x + 65 = 0 \\ 97 - 64x = 0 \\  - 64x =  - 97 \\ divide \: both \: side \: by \:  - 64 \\ x =  \frac{97}{64}

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Answer:

47

Step-by-step explanation:

Let's solve your equation step-by-step.

−4x−3(−44−23)=13

Step 1: Simplify both sides of the equation.

−4x+201=13

Step 2: Subtract 201 from both sides.

−4x+201−201=13−201

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Step 3: Divide both sides by -4.

−4x

−4

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3 0
2 years ago
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iragen [17]

Answer:

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2 years ago
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JulsSmile [24]

Answer:

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3 years ago
What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to
Assoli18 [71]

Answer:

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Step-by-step explanation:

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Step 2: Subtract 41 from both sides.

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