Question

Find the perimeter of the following shape, rounded to the nearest tenth:

Answer 1

Answer:

19.1 units

Step-by-step explanation:

Sides CB and DA your length are equals

Sides AB and DC your length are equals

Using the Pythagoras Theorem:

c² = a² + b²

Side AB:

c² = 1² + 5²

c² = 1 + 25

c² = 26

√c² = √26

c = 5.1     aprox.

Side CB:

c² = 2² + 4²

c² = 4 + 16

c² = 20

√c² = √20

c = 4.472     aprox

then:

the perimeter:

p = AB + BC + CD + DA

AB = CD = 5.1

DA = BC = 4.472

p = 2(5.1 + 4.472)

p = 2(9.572)

p = 19.144    aprox.

then the correct optión is:

19.1 units

Answer 2

Answer:

P = 18.4 units

Step-by-step explanation:

Sides AB and CD are congruent and thus have the same length.

Sides AD and BC are congruent.

The length of side AB is found using the Pythagorean Theorem:

|AB| = √ [ 5² + 1² ] = √26

and

|BC| = √ [ 4² + 1² ] = √17

Then the perimeter is P = 2(√26) + 2(√17), or

                                           10.20    +  8.25, or, to the nearest tenth,

                                      P = 18.4 units