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Bumek [7]
4 years ago
14

In George’s neighborhood there are 33 cats and 33 dogs roaming free.What percent of the animals roaming free are dogs?

Mathematics
1 answer:
Alexxx [7]4 years ago
6 0
First, we'll figure out how many animals there are in total by adding up the cats and the dogs. In this case, we have 33+33=66 total animals. Then we need to figure out what fraction of these 66 animals are dogs:
\frac{33}{60}=\frac{1}{2}

So half of the animals are dogs. To write that as a percent, we need the fraction to be over 100, so:
\frac{1}{2}=\frac{50}{100}

50% of the animals are dogs.
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The table shows the type of super power students wish they had. Super power Students Flight 888 Super strength 101010 X-ray visi
pogonyaev

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4 years ago
This composite shape is a rectangle with a semicircle attached on one end. The diameter of the semicircle is 6 feet.
Ugo [173]

As we can see on the picture we have a rectangle and half of circle.

The areas for half circle and rectangle are:

A_{rectangle}=a\cdot b \\A_{halfcircle}=\frac{A_{circle}}{2}=\frac{\pi r^2}{2}

The area of the figure is the sum of the area of half circle and rectangle. Also the height of a rectangle (6ft) is a diameter of a half circle therefore the radius of half circle is 6ft ÷ 2 = 3ft.

Now we calculate the areas.

A_{rectangle}=10\cdot 6=\underline{60} \\A_{halfcircle}=\frac{3.14\cdot3^2}{2}=\underline{14.13} \\A_{total}=A_{rectangle}+A_{halfcircle} =60+14.13=\boxed{74.13\approx74}

The area of the figure is approximately 74ft squared.

Hope this helps.

r3t40

3 0
3 years ago
Read 2 more answers
A survey of the students in Lance’s school found that 58% of the respondents want the school year lengthened, while 42% think it
alina1380 [7]
The margin of error of a given statistic is an amount that is allowed for in case of miscalculation or change of circumstances.

It is usually the radius or half of the width of the confidence interval of that statistic.

Given that a<span> survey of the students in Lance’s school found that 58% of the respondents want the school year lengthened, while 42% think it should remain the same. The margin of error of the survey is ±10%.

This means that 58% </span><span>± 10% of the </span>respondents want the school year lengthened, while 42% <span><span>± 10% think it should remain the same.</span>

Thus, from 48% to 68% </span><span><span>of the respondents want the school year lengthened, while from 32% to 52% <span>think it should remain the same.</span> </span>

Therefore, according to the survey data, at least 32% of students want the duration of the school year to remain unchanged, and at least 48% want the school year to be lengthened.</span>
7 0
3 years ago
I need help.. PLEASE HELP ME WITH SOME QUESTIONS I HAVE ON ALGEBRA
alukav5142 [94]
Okay post them 1 at a time
5 0
3 years ago
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