Katie has read 32%, so 32%=80 pages. To get the total number of pages, you have to divide 32 and 80 by 8 to get 4% and 10 pages. 4% of the book is 10 pages, and in order to get 100%, you have to multiply by 25(4*25=100) on both sides. Remember, what you do to one side, you do to the other side. That leaves you with 100% and 250 pages. The book is 250 pages long. If she has read 80 pages, you subtract 80 from 250 to find how many pages she has left to read. The difference is 170. Katie has 170 pages left to read.
The first one is correct :-)
Answer:
a) 
b) 
Dividing both sides by 0.448 we got:
We can appy the exponent 
in both sides of the equation and we got:
Step-by-step explanation:
For this case we know the following function:
The notation is: x is the weight of the crab in grams, and the output f(x) is the weight of the claws in grams.
Part a
For this case we just need to replace x = 2 gram in the function and we got:
Part b
For this case we know tha value for 
and we want to find the value of x who satisfy this condition:
Dividing both sides by 0.448 we got:
We can appy the exponent in both sides of the equation and we got:
A two digit number has a tens digit and a ones digit.
Let's say x = tens digit and y = ones digit
"The sum of the digits is 5"
x + y = 5
The next phrase is "the number multiplied by 3 is 42" but we need to represent the number using the digits. So they need to be multiplied first by their place value and added together. [Example: 34 = 3(10) + 4(1)]
The number is: 10x + y
3(10x + y) = 42
The system of equations: (two equations for two unknowns)
x + y = 5
30x + 3y = 42
Then you can use substitution or elimination to combine and solve.
I'll use elimination, multiply the entire top equation by -3 and add the equations together. y will cancel out
-3x - 3y = -15
30x + 3y = 42
------------------
27x + 0 = 27
x = 1
then plug x = 1 into either equation to find y
1 + y = 5
y = 4
remember the x and y represent digits so the number xy is 14
Answer:
I think it's the top left one
Step-by-step explanation:
