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4 years ago

What is the translation for this graph?

Mathematics

1 answer:

Schach [20]4 years ago

3 0

Answer:

ok so meet x-3 and y -4 in the middle were they meet if the y and x confuse you take them off and then do the same for the rest of them this - symbel means negitive and this one means + positive if you have more qeustions just ask

Step-by-step explanation:

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Given f (x)=2x-5x-3 and g (x)=2x^2+x what is (f/g)(x)<br>

Rufina [12.5K]

ANSWER

$( \frac{f}{g} )(x ) = \frac{x - 3}{x} \: where \: \: x \ne0, - \frac{1}{2}$

EXPLANATION

Given:

$f(x) = 2 {x}^{2} - 5x - 3$

and

$g(x) = 2 {x}^{2} + x$

Then,

$( \frac{f}{g} )(x ) = \frac{f(x)}{g(x)}$

Substitute the given functions;

$( \frac{f}{g} )(x ) = \frac{2 {x}^{2} - 5x - 3}{2 {x}^{2} + x}$

Factor

$( \frac{f}{g} )(x ) = \frac{2 {x}^{2} - 6x + x - 3 }{x(2x + 1)}$

$( \frac{f}{g} )(x ) = \frac{2x(x - 3) +1 (x - 3)}{x(2x + 1)}$

$( \frac{f}{g} )(x ) = \frac{(2x + 1)(x - 3) }{x(2x + 1)}$

Cancel the common factors.

$( \frac{f}{g} )(x ) = \frac{x - 3}{x} \: where \: \: x \ne0, - \frac{1}{2}$

3 0

3 years ago

If a=2 b=1 find the value of a square minus b square

Usimov [2.4K]

<em>The answer is 3</em>

a= 2, b=1,

a²-b² = 2²-1²= 4-1 =3

6 0

3 years ago

What is the simplified form of the following expression? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0 2

finlep [7]

To solve such questions we need to know more about expression.

<h2 /><h2>Expression </h2>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations that are formed according to rules which are dependent on the context.

<h2 /><h2 /><h2>Given to us,</h2>

$2\sqrt[4]{16x}-2\sqrt[4]{2y}+3\sqrt[4]{81x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-16\sqrt[4]{2y}+13\sqrt[4]{4}-10\sqrt[4]{2y}+35\sqrt[4]{x}-18\sqrt[4]{2y}$

rearranging we get,

$=2\sqrt[4]{16x}+3\sqrt[4]{81x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{4}+35\sqrt[4]{x}-2\sqrt[4]{2y}-4\sqrt[4]{32y}-4\sqrt[4]{32y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$

we know that,

$\sqrt[4]{81}=3\\\sqrt[4]{16}=2\\\sqrt[4]{32}=2\sqrt[4]{2}\\$

therefore,

$=4\sqrt[4]{x}+9\sqrt[4]{x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{x}+35\sqrt[4]{x}-2\sqrt[4]{2y}-8\sqrt[4]{2y}-8\sqrt[4]{2y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$