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asambeis [7]
4 years ago
10

Can you help me with 10-13 please? I don’t really understand it

Mathematics
1 answer:
Verdich [7]4 years ago
5 0
The answer 0 10_13 --0 zero
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a boy agreed to work one year for 1200 and a horse at the end of six months he quit and received 400 plus the horse what was the
Arisa [49]

The cost of the horse given the amount received at the end of 6 months is 600

<h3>How to find the value of the horse?</h3>

let

  • h = value of the horse

6/12 × 1200 + 6h/12 = 400 + h

700 + 6h / 12 = 400 + h

700 - 400 = h - 6h/12

300 = 12h - 6h / 12

300 = 6h/12

  • cross product

300 × 12 = 6h

3600 = 6h

h = 3600 / 6

h = 600

Learn more about cost of items:

brainly.com/question/19104371

7 0
2 years ago
HELPPPPPPPPPPPPPPPPPPPPP
Vesna [10]

Answer:

Angles

Step-by-step explanation:

A polygon is a shape, I don't think there are conversions since a polygon is not something you can measure. A population can be counted with normal numbers, 1,2,3... density is calculated with mass and volume, not radians and degrees.... yeah.

Angles are measured in radians and degrees, so it's angles.

5 0
2 years ago
Read 2 more answers
A box contains 20 lightbulbs, of which 5 are defective. If 4 lightbulbs are picked from the box randomly, the probability that a
madam [21]

Answer:

Option D. 938/969

Step-by-step explanation:

At most 2 defective means 2 or less than 2 bulbs are defective

So, we have 3 cases:

a) No defective bulb.       b) 1 defective bulb.      c) 2 defective bulbs

Case a) No defective bulb

Total number of bulbs = 20

Number of defective bulbs = 5

Number of non-defective bulbs = 15

Total number of ways to select 0 defective bulb = 15C4 = 1365

Case b) 1 defective bulb

Total number of ways to select 1 defective bulb = 15C3 x 5C1 = 2275

Case c) 2 defective bulbs

Total number of ways to select 2 defective bulbs = 15C2 x 5C2 = 1050

Therefore, total number of ways to select at most 2 defective bulbs = 1365 + 2275 + 1050 = 4690

Total number of ways to select 4 bulbs from 20 = 20C4 = 4845

Therefore, probability of selecting at most 2 defective bulbs = \frac{4690}{4845}=\frac{938}{969}

Therefore, option D gives the correct answer.

6 0
4 years ago
Which of these best explains the next step to simplify this expression? 3y−45=35y−4 Question 22 options: Make the –4 exponent in
NISA [10]

The value of y from the give expression is 1

<h3>Expressions and equations</h3>

Give the following expression

\frac{3y^{-4}}{5} = \frac{3}{5y^{-4}}

Cross multiply the given expression

3y^{-4}\times 5y^{-4}= 5 \times 3\\15y^{-8}=15\\

Divide both sides by 15

y^{-8}=1\\\frac{1}{y^8} =1\\y^8=1\\y=1

Hence the value of y from the given expression is 1

Learn more on indices here: brainly.com/question/10339517

3 0
3 years ago
Which of the pairs of angles are vertical angles and thus congruent? ∠A and ∠G ∠A and ∠B ∠C and ∠F ∠D and ∠H
r-ruslan [8.4K]

Answer:

∠A and ∠G is the pair of vertical angles.

Step-by-step explanation:

From the figure attached,

Two lines 'm' and 'n' are two parallel lines. These lines intersect a horizontal line 'l'.

Since, "Pair of opposite angles formed at the point of intersection are the vertical angles and equal in measure."

Therefore, Opposite angles ∠A ≅ ∠G, ∠B ≅ ∠H, ∠C ≅ ∠E and ∠D ∠F are the vertical angles.

From the given options,

∠A and ∠G is the pair representing the pair of vertical angles and thus congruent.

5 0
3 years ago
Read 2 more answers
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