Hey there!!
Given equation :
... c(x) = 29x + 54.5
<em>In this equation $54.50 is installation fee and this would remain as a constant. ( This value wouldn't change ). </em>
<em>'x' is represented as the number of months. </em>
The total cost or c(x) is given as $344.50
Getting this into equations :
... 344.50 = 29x + 54.5
Subtracting 54.5 on both sides :
... 29x = 290
Dividing by 29 on both sides :
... x = 10
<u><em>Hence, the number of months is 10. </em></u>
Hope my answer helps!!
<span>(2p + q) ( –3q – 6p + 1)
= -6pq - 12p^2 + 2p - 3q^2 - 6pq + q
= -12p^2 -12pq +2p -3q^2 + q
so answer is b. </span> -12p^2 -12pq +2p -3q^2 + q
It would be A=18 because of the equation a^2+b^2=c^2.
The answer to this is 392
