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3 years ago

Se x e um número real tal que 3x +1/2 > 2x - 5, então podemos afirmar que;

Mathematics

1 answer:

Crazy boy [7]3 years ago

7 0

Step-by-step explanation:

$3x + \frac{1}{2} > 2x - 5 \\ x > - 5 \frac{1}{5}$

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The table shows the number of minutes Garrett practiced his trombone each week in one month. Week Number of Minutes Practiced 1

vredina [299]

Answer:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

The reason is because we assume that each week have the same weight and replacing we got:

$\bar X= \frac{190+163+327+205}{4}= 221.25$

And the best option would be:

D. 221.25

Step-by-step explanation:

For this case we have the following data given

Week 1 2 3 4

Minutes 190 163 327 205

For this case we can find the mean with the following formula:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

The reason is because we assume that each week have the same weight and replacing we got:

$\bar X= \frac{190+163+327+205}{4}= 221.25$

And the best option would be:

D. 221.25

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4 years ago

The number of cars sold at a dealership over several weeks is given below.

andrezito [222]

Answer:

A. 6.9

Step-by-step explanation:

Edge 2020

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3 years ago

506,709 in word form

77julia77 [94]

Five hundred six thousand seven hundred and nine.

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4 years ago

Read 2 more answers

To the nearest tenth, find the perimeter of ABC with vertices A(-1,4), B(-2,1) and C(2,1). show your work

liubo4ka [24]

we have to firstly apply the distance formula to find the length of sides of the triangle

distance formula = $\sqrt{(x_{2} -x_{1})^2 +(y_{2}- y_{1})^2}$

So length AB = $\sqrt{(-2-(-1))^2+(1-4)^2}= \sqrt{1 +9}=\sqrt{10}$

BC= $\sqrt{(2-(-2))^2+(1-1)^2}= \sqrt{16+0}=4$

AC = $\sqrt{(2-(-1))^2+ (1-4)^2}= \sqrt{9+9}=\sqrt{18}=3\sqrt{2}$

Now perimeter = AB+BC+AC = $\sqrt{10}+4+3\sqrt{2}$

Plug in calculator

perimeter= 11.4 units

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3 years ago

3. Which situation is best described by the graph shown?

Alex73 [517]

There is no graph doe ...

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3 years ago