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Alex777 [14]
3 years ago
12

17.2 writes it as a mixed number in lowest terms

Mathematics
1 answer:
bixtya [17]3 years ago
3 0
1/5 as a mixed number
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SOMEONE HELP PLEASE I WIL GIVE BRAinlest could yu please help answer 1-9 and I would really be grateful if you explained how you
ser-zykov [4K]

Answer: For the first one, 12.5% chance

Step-by-step explanation:

The probability of flipping a coin and getting tails is 50%. Then, if you were to flip two coins and get both tails, you would have to divide the 50% by 2, which is equals to 25% of flipping two coins and getting them both tails.

So now we know...

Flipping one coin gives you 50% tails and 25% of flipping two coins and getting two tails

So now, we do it again with the third coin. We would divide the 25% by 2, which will get us to a 12.5% of getting all tails, or in fractions, 1/8

I’m not exactly sure about the other ones but I hope you found this one helpful!

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I think the Answer is 76 in^2

Hope this helps

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Please help! Segment QR is tangent to circle P at point Q. What is the measure of angle PQR? A.) 37 degrees B.) 53 degrees C.) 9
Andrew [12]

Answer:

Correct option: C) 90 degrees

Step-by-step explanation:

When we have a tangent segment to a circle, the angle made with the radius of the circle and the tangent segment is always a right angle, that is, 90 degrees. In other words, the radius and the tangent segment are always perpendicular.

If QR is tangent to the circle P, and PQ is the radius of the circle, the segment PQ is perpendicular to the segment QR, so the angle PQR is equal 90 degrees.

Correct option: C)

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A rectangle has an area of 165 square yards. It has a height of 5 yards. What is its base? (Hint: A ÷h=b)​
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3 years ago
The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota
Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

a.

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

b.

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

8 0
3 years ago
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