Answer: C . 147π / 4 mi²
Concept:
The sector is the part of a circle is enclosed by two radii of a circle and their intercepted arc.
A = (θ / 360) πr²
θ = angle of the sector
π = constant
r = radius
Solve:
<u>Given variable</u>
θ = 270°
r = 7 mi
<u>Given formula</u>
A = (θ / 360) πr²
<u>Substitute values into the formula</u>
A = (270 / 360) π (7)²
<u>Simplify exponents</u>
A = (270 / 360) π 49
<u>Simplify by multiplication</u>
A = (147 / 4) π
A = 147π / 4
Hope this helps!! :)
Please let me know if you have any questions
What are you trying to do here?
Solve the graph, or make it appear as something else?
First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0
sec (x) (2sec (x) -2) = 0
Then we're going to separate the two to find the zeros of each because anything time 0 is zero.
sec(x) = 0
2sec (x) - 2 = 0
Now, let's simplify the second one as the first one is already.
Add 2 to both sides:
2sec (x) = 2
Divide by 3 on both sides:
sec (x) = 1
I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
Answer:
2.20752 x 
Step-by-step explanation:
The first thing you have to do is to look for the number of seconds in one year. You have to multiply 365 days by 86,400 seconds.
- 365 days refer to the total number of days per year
- 86,400 seconds refer to the number of seconds per day
Let's solve.
- 365 x 86,400 = 31,536,000 or 3.1536 x

<em>Therefore, one year has 3.1536 x </em>
<em> seconds.</em>
Next, you have to know the number of seconds in 10 billion years.
- (3.1536 x
) x (1.0 x
) = 3.1536 x 
The last step is to multiply the number of seconds in 10 billion years to 7 million tons of mass per second.
- (3.1536 x
) x 7,000,000 = 2.20752 x 
Ok, for multiplication of fractions you do not need a common denominator so multiply top by top and bottom by bottom... let me know what you get
Answer:
mee
Step-by-step explanation: