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3 years ago

Is 2 between 1.3 an 1.4

Mathematics

2 answers:

nikdorinn [45]3 years ago

5 0

No it is not your welcome ;)

ser-zykov [4K]3 years ago

4 0

Nope because 1.3 and 1.4 comes before 2 so it can't be between them

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The formula K=59(F−32)+273.15 converts temperatures from Fahrenheit F to Kelvin K.

Semmy [17]

Answer:

9/5 (K-273.15) + 32=F

Step-by-step explanation:

K=5 /9(F−32)+273.15

Subtract 273.15 from each side

K-273.15=5/9(F−32)+273.15-273.15

K-273.15=5/9(F−32)

Multiply by 9/5 on each side

9/5 (K-273.15)= 9/5 *5/9(F−32)

9/5 (K-273.15)=(F−32)

Add 32 to each side

9/5 (K-273.15) + 32=F−32 +32

9/5 (K-273.15) + 32=F

4 0

3 years ago

Read 2 more answers

A box is 50 cm long. Which of these is closest to the length of this box in feet? (1 inch = 2.54 cm)

goblinko [34]

First, convert cm to inches.

50/2.54 is roughly 19.69

There are 12 inches in a foot, so divide the 19.69 by 12.

19.69/12 is roughly 1.64

So the answer is C

3 0

3 years ago

PLEASE HELP ME OUT ASAP! I WOULD REALLY APPRECIATE IT AND GOD BLESS

77julia77 [94]

To approximate the P(x<27) we need to find the z-score of the data, this will be given by:
z=(x-μ)/σ
where:
μ-mean
σ-standard deviation
x=27, μ=32, σ=4
z=(27-32)/4
z=-5/4
z=-1.25
thus
P(x<27)=P(z<-1.25)
=0.1056
=10.56%

Answer: 10.56%

5 0

3 years ago

I need help with a math question

adoni [48]

6/8+7/8=13/8 or 1 5/8

4 0

3 years ago

A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.

kondor19780726 [428]

Answer:

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

Step-by-step explanation:

The kittens are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.

This means that $N = 8 + 10 = 18$

We want 3 boys, so $k = 8$

The director is going to choose 8 of these kittens at random to be in the commercial.

This means that $n = 8$

What is the probability that the director chooses 3 boy kittens and 5 girl kittens?

This is P(X = 3).

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 3) = h(3,18,8,8) = \frac{C_{8,3}*C_{10,5}}{C_{18,8}} = 0.323$

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

3 0

3 years ago