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elena-14-01-66 [18.8K]
3 years ago
11

(x+3)² how do i solve

Mathematics
1 answer:
Mila [183]3 years ago
3 0
X2+9+6
 hope this helps
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Six times one hundred thirty one .four
Nonamiya [84]

Answer:

786

Step-by-step explanation:

6•1=6

6•30=180

6•100=600

600+180+6=786

6 0
4 years ago
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Me ayudan en esto? es de matemáticas año 1 de completen factors​
Marina CMI [18]

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(3p-2)(2p+3).

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Group 5?<br><br> 2x+8=5x+4<br><br> are any of you there?
Vesnalui [34]

Step-by-step explanation:

8-4=5x-2x =4=3x=4/3 =3x/3 x=1.5

7 0
3 years ago
What is the answer for (x-3) (x 3) = 8x?
7nadin3 [17]
82 I think is your answer
5 0
3 years ago
Find all the zeros of the equation.
Serhud [2]
You can either use the Pythagorean theorem right away (a = -3, b = 27, c = 1200) or Try factoring the polynomial to find the zeros.

I would factor and start by dividing everything by -3.

<span>-3x^4 + 27x^2 + 1200 = 0
-3(x^4 - 9x^2 - 400) = 0

If you divide by -3 on both sides you see that the -3 is now gone. 0/-3 = 0

x^4 - 9x^2 - 400 = 0
factor further or use Pythagorean theorem.

(x² - 25)(x² + 16) = 0

Solve for the x-values by setting each one equal to zero.

x² - 25 = 0
x² = 25
x is +5 or -5

x² + 16 = 0
x² = -16
x = √(-16)
Two non-real solutions
x is +4i or -4i

</span>
3 0
4 years ago
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