Answer:
13.695 m
Step-by-step explanation:
The assumption made here is that the boat/water interface is essentially frictionless, so that the center of mass of the system remains in the same place as the occupant of the boat moves around.
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We can find the sum of the moments of boat and child about the pier end:
(46 kg)(7.6 m) + (80 kg)((7.6 +9.6/2) m) = 1341.6 kg·m
After the child moves, the center of mass of boat and child is presumed to remain in the same place. If x is the new distance from the pier to the child, the sum of moments is now ...
46x +80(x-4.8)* = 1341.6
126x -384 = 1341.6
x = (1341.6 +384)/126 = 13 73/105 ≈ 13.695 . . . meters
The child is about 13.695 meters from the pier when she reaches the far end of the boat.
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* The center of mass of the boat alone is half its length closer to the pier than is the child, so is located at x-4.8 meters.
Blue balls : Total number.
Total number of balls = 50 + 45 + 65 = 160
Blue balls : Total number.
= 65: 160 Divide both by 5.
= 13 : 32
= 13/32. That is the ratio.
angles a and b are supplementary because they form a straight line
Answer:
If i did this right the answer would be f(2)=g(2)
both numbers are 2 and the numbers are (x) so x=2
Step-by-step explanation:
Hope this helps Kas <33
Answer:
2
Step-by-step explanation:
it has 2 in the equation
