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EleoNora [17]
2 years ago
11

In a candy mix there are 4 green bars for every 3 red bars how many red bars are ther if there are 200 green bars

Mathematics
2 answers:
nexus9112 [7]2 years ago
5 0
200 <span>÷ 4 = 50 (4 bars, 200 total)
50 x 3 = 150 (Above answer times 3 red)
So if there are 200 greens and every 4 green there's 3 red, then there would be
150.</span>
puteri [66]2 years ago
3 0
Set up a proportion.
Solve for x

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1x+5=10 pls do it for me i'll give you brainly
STatiana [176]

1x+5=10

1x-5=10

x=5 that is the answer to the question hoped it helped.

4 0
3 years ago
Read 2 more answers
destiny sells pencil cases for $5 each and mechanical pencils for $2 each at the school supply store. she sells p pencil cases a
Andrew [12]

Answer:

Step-by-step explanation:

5p + 2(p + 4) .......because pencil cases (p) sell for 5 bucks a piece....and mechanical pencils (p + 4), sell for 2 bucks a piece. She is basically selling 4 more mechanical pencils then she is pencil cases.

8 0
3 years ago
Sadiq measured the dimensions of a 1 kg bag of sugar and found the length was 9.2 cm, the width was 6 cm and the height was 14.1
garik1379 [7]

Answer:

d=1.28\times 10^{-6}\ g/cm^3

Step-by-step explanation:

The mass of a bag of sugar, m = 1 kg = 0.001 g

Length of bag, l = 9.2 cm

Width of bag, b = 6 cm

Height of the bag, h = 14.1 cm

We need to find the density of the sugar bag.

Density = mass/volume

So,

d=\dfrac{0.001\ g}{9.2\times 6\times 14.1\ cm^3}\\\\d=1.28\times 10^{-6}\ g/cm^3

So, the density of the bag is 1.28\times 10^{-6}\ g/cm^3.

7 0
2 years ago
If x = 8 units, y = 3 units, and h = 2 units, then what is the area
solniwko [45]

Answer:

8 sq.units

Step-by-step explanation:

x= base of triangle= 8units

h= height of triangle= 2 units

area of triangle= 1/2*b*h

=1/2* 8* 2

=8 sq.units

<em>Mark me as brainliest please</em>

7 0
2 years ago
Questlon 4 of 10
Kisachek [45]

Answer:

c

Step-by-step explanation:

<em>To </em><em>find </em><em>the </em><em>midpoint</em><em> </em><em>the </em><em>formulas</em>

<em>x=</em><em>x1+</em><em>x2/</em><em>2</em><em> </em><em>and </em><em>y</em><em>=</em><em>y1+</em><em>y2/</em><em>2</em><em> </em><em>are </em><em>used </em>

<em>in </em><em>this </em><em>case </em><em>x1 </em><em>is </em><em>5</em><em>,</em><em>x2 </em><em>is </em><em>5</em><em>,</em><em>y1 </em><em>is </em><em>4</em><em> </em><em>and </em><em>y2 </em><em>is </em><em>-</em><em>3</em>

<em>therefore</em>

<em>x=</em><em>5</em><em>+</em><em>5</em><em>/</em><em>2</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em> </em><em> </em><em>=</em><em>1</em><em>0</em><em>/</em><em>2</em>

<em> </em><em> </em><em>=</em><em>5</em>

<em>y=</em><em>4</em><em>+</em><em>(</em><em>-</em><em>3</em><em>)</em><em>/</em><em>2</em>

<em> </em><em> </em><em>=</em><em>1</em><em>/</em><em>2</em>

3 0
3 years ago
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