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algol [13]
3 years ago
7

Writing the range f(x)=abx

Mathematics
1 answer:
Art [367]3 years ago
4 0
Oh I’m so bad at these I am so sorry for wasting your time.
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Please answer as many as you can.
dimaraw [331]

Answer: okay so your problems are like 10000000k through  out resons of dum. so x=-1. is a little wrong becayse the x = into a 1 so  you make the 1 that factor. so thats why answer for 2.5

Step-by-step explanation:

6 0
3 years ago
Albert bought 3 blank tapes for $5.95. Find the cost per tape to the nearest cent.​
Brilliant_brown [7]

Answer:

17.85

Step-by-step explanation:

just times 5.95 by 3

4 0
3 years ago
Can someone help me with these two problems and show work please !!
irina1246 [14]
Work is attached to this post

5 0
2 years ago
Read 2 more answers
Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distribut
defon

Answer:

0.8665 = 86.65% probability that the sample mean would be at least $39000

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125:

This means that n = 125, s = \frac{7320}{\sqrt{125}} = 654.72

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{654.72}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

0.8665 = 86.65% probability that the sample mean would be at least $39000

4 0
3 years ago
which pair of ratios is equivalent 8:32 and 16:64 or 52:56 and 17:19 or 34:40 and 16:20 or 6:8 and 16:12 help immediately
choli [55]
As it a lowest one so you will have to double it It is 16:64
6 0
3 years ago
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