Answer:
A= 16
P=16
Step-by-step explanation:
A=h^bxb/ 2
P= side+base+side
Answer:
x>-1/3
Step-by-step explanation:
−3x<−18+19
−3x<1
x>− 1/3
Initially, Ball A of 10 kg will have velocity x, while Ball B of 30 kg has velocity -10 m/s.
After collision, Ball A will have a velocity of -30 m/s, while Ball B will have velocity 10 m/s. We assume their masses do not change.
(10 kg)(x m/s) + (30 kg)(-10 m/s) = (10 kg)(-30 m/s) + (30 kg)(10 m/s)
10x - 300 = -300 + 300
x = 30 m/s (to the right)
2x + y = -3
x - 2y = -4
2x + y = -3
2x - 4y = -8
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5y = 5
y= 1
2x + y = -3
2x + (1) = -3
2x = -4
x = -2
Solution: x = -2, y = 1
2 × 4 is a way to use multipacation
