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tester [92]
3 years ago
10

Mr. Rutherford's chemistry class was collecting data in a neutralization study. Each group had 24 test tubes to check each day f

or one week. Students had to check to see whether the solution in each test tube was acidic, basic, or neutral. What would be the MOST efficient method for collecting this data and recording it for later analysis? A) pH paper and a notebook B) pH probe linked to a graphing calculator C) photometer linked to a graphing calculator D) phenolphthalein solution and a computer spreadsheet
Chemistry
1 answer:
ycow [4]3 years ago
6 0
I’m pretty sure it is A at least that’s what we did at our school to test this
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An acetic acid buffer solution is required to have a pH of 5.27. You have a solution that contains 0.010 mol of Acetic acid. Wha
dlinn [17]

Answer:

Molarity of sodium acetate you will need to add is 0.0324M

Explanation:

<em>Assuming volume of the buffer is 1L.</em>

<em />

The pH of a buffer can be determined using Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where pKa is pKa of the weak acid,  [A⁻] molar concentration of conjugate base and [HA] molar concentration of weak acid</em>

<em />

Replacing for the acetic buffer (pKa = 4.76):

pH = 4.76 + log [Sodium Acetate] / [Acetic Acid]

As you have 0.010 moles of acetic acid in 1L:

[Acetic Acid] = 0.010mol / 1L = 0.010M

And you require a pH of 5.27:

5.27 = 4.76 + log [Sodium Acetate] / [0.010M]

0.51 = log [Sodium Acetate] / [0.010M]

10^0.51 = [Sodium Acetate] / [0.010M]

3.236 =  [Sodium Acetate] / [0.010M]

3.236 [0.010M] = [Sodium Acetate]

0.0324M = [Sodium Acetate]

<h3>Molarity of sodium acetate you will need to add is 0.0324M</h3>

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7 0
3 years ago
Determine the number of HC=CH, monomeric units in one molecule of polyethylene with a molar
VladimirAG [237]

polyethylene contains HC=CH units.

mass of this is 26 gram/mol

number of such units =13500/26

3 0
3 years ago
If aqueous solution of lead (ll) nitrate and sodium sulfate, which insoluble precipitate is formed
forsale [732]

Answer:

Lead(II) sulfate

Explanation:

This looks like a double displacement reaction, in which the cations change partners with the anions.

The possible products are

Pb(NO₃)₂ (aq)+ Na₂SO₄(aq) ⟶PbSO₄(?) + 2NaNO₃(?)

To predict the product, we must use the solubility rules. Two important ones for this question are:

  1. Salts containing Group 1 elements are soluble.
  2. Most sulfates are soluble, but PbSO₄ is an important exception.

Thus, NaNO₃ is soluble and PbSO₄ is the precipitate.

7 0
3 years ago
What are solids at room temperature and conduct electricity and heat?
ddd [48]
Metals are lustrous, malleable, ductile, good conductors of heat and electricity. Other properties include: State: Metals are solids at room temperature with the exception of mercury, which is liquid at room temperature
8 0
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Complete this equation for the dissociation of K3PO4(aq). Omit water from the equation because it is understood to be present.
Anna35 [415]
Balanced chemical reaction (dissociation): K₃PO₄(aq) → 3K⁺(aq) + PO₄³⁻(aq).
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In water potassium phosphate, ionic compound, dissociates on positive potassium ion (cations) and negative phosphate ions (anions).
Potassium has positive charge (+1), compound has neutral charge.
3 0
3 years ago
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