Answer:
MM = 5,521.54 g/mol
Explanation:
To solve this, we need to use the expression for osmotic pressure which is the following:
π = MRT (1)
Where:
M: Concentration of the solution
R: gas constant (0.082 L atm/ mol K
T: temperature in K
25 °C in Kelvin is: 25 + 273.15 = 298.15 K
Now, we do not have the concentration of the solution, but we do have the mass. and the concentration can be expressed in terms of mass, molar mass and volume:
Concentration (M) is:
M = n/V (2)
and n (moles) is:
n = m/MM (3)
Therefore, if we replace (2) and (3) in (1) we have:
π = mRT/V*MM
Solving for MM we have:
MM = mRT/πV (4)
All we have to do now, is replace the given data and we should get the value of the molar mass:
MM = 6.143 * 0.082 * 298.15 / 0.1 * 0.272
MM = 150.1859 / 0.0272
<em>MM = 5,521.54 g/mol</em>
<em>This is the molar mass.</em>
Answer:
Response is below
Explanation:
The different types of mining are underground, surface, placer, and in-situ. Underground mining uses various materials to excavate resources from beneath the surface of the Earth. Surface mining is a category of mining that in which soil and rock overlying the mineral deposit are removed. Placer mining is the mining of stream bed deposits for minerals. In-situ mining is a mining process used to recover minerals such as copper and uranium through boreholes drilled into a deposit.
Answer:
Hydrogen. Symbol: H. Atomic Weight: 1.008. ...
Magnesium. Symbol: Mg. Atomic Weight: 24.305. ...
Aluminum. Symbol: Al. Atomic Weight: 26.9815385. ...
Phosphorus. Symbol: P. ...
Chlorine. Symbol: Cl. ...
Argon. Symbol: Ar. ...
Potassium. Symbol: K. ...
Calcium. Symbol: Ca.
C16H32O2(aq) --> 16CO2(g) + 16H2O(l) ... said its wrong though?
<span>This is because you haven't added any oxygen needed for the combustion, so your equation does'nt balance. Also a solution in water [aq] doesn't burn! </span>
<span>Try </span><span>C16H32O2(s) + 23O2(g) --> 16CO2(g) + 16H2O(l)
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
</span>
<span>decomposition of SrCO3 to SrO and CO2 =change in mass
moles of CO2 =(1.850 g - 1.445 g).
</span>Mass of <span>C<span>O2</span></span><span> in mixture: 1.850-1.445 = 0.405g
</span>0.405g/44.01 g/mol <span>C<span>O2</span></span><span> = 0.0092 moles </span><span>C<span>O2</span></span><span>.
</span>ratio of <span>C<span>O2</span></span><span> to SrO in Sr</span><span>C<span>O3</span></span><span> is 1:1
</span><span> mass ratio = 1.358/1.850 = 0.7341, </span>
or 73.41% Sr<span>C<span>O3</span></span><span>.
</span>hope this helps
