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Savatey [412]
3 years ago
6

Which landforms might you see at a divergent plate boundary? Check all that apply. mid-ocean ridge mountain range rift valley vo

lcano island
Chemistry
2 answers:
Vesnalui [34]3 years ago
7 0

Answer:

a and c

Explanation:

Gwar [14]3 years ago
5 0

Answer:

A. mid-ocean ridge

C. rift valley

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What % of baking soda (NaHCO3) is hydrogen?
lorasvet [3.4K]

Answer:

Components present of sodium bicarbonate

Sodium bicarbonate is formed by mixing carbon, sodium, hydrogen and oxygen molecules. This mixture, also known as baking soda, is actually a type of salt.

Explanation:

6 0
2 years ago
In a solution, when the suspension of one kind of molecules is blended or dissolved with another, the ________ properties are no
Sidana [21]

Answer:

chemical

Explanation:

The chemical properties determine the identity of a substance and are not changed when there is no reaction. In the solution, what takes place is a physical change, which is a change of state (for example, going from solid to aqueous form).

8 0
3 years ago
The chemical equation shows iron(III) phosphate reacting with sodium sulfate. 2FePO4 + 3Na2SO4 Fe2(SO4)3 + 2Na3PO4 What is the t
slava [35]

<u>Answer:</u> The theoretical yield of iron(III) sulfate is 26.6 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of iron(III) phosphate = 20.00 g

Molar mass of iron(III) phosphate = 150.82 g/mol

Putting values in equation 1, we get:

\text{Moles of iron(III) phosphate}=\frac{20g}{150.82g/mol}=0.133mol

The given chemical equation follows:

2FePO_4+3Na_2SO_4\rightarrow Fe_2(SO_4)_3+2Na_3PO_4

As, sodium sulfate is present in excess. So, it is considered as an excess reagent.

Thus, iron(III) phosphate is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of iron(III) phosphate produces 1 mole of iron(III) sulfate

So, 0.133 moles of iron(III) phosphate will produce = \frac{1}{2}\times 0.133=0.0665moles of iron(III) sulfate

Now, calculating the mass of iron(III) sulfate from equation 1, we get:

Molar mass of iron(III) sulfate = 399.9 g/mol

Moles of iron(III) sulfate = 0.0665 moles

Putting values in equation 1, we get:

0.0665mol=\frac{\text{Mass of iron(III) sulfate}}{399.9g/mol}\\\\\text{Mass of iron(III) sulfate}=(0.0665mol\times 399.9g/mol)=26.6g

Hence, the theoretical yield of iron(III) sulfate is 26.6 grams

8 0
3 years ago
If 100 ml of a 0.5 M HCI Solution is diluted with water to 1000ml, what is the new concetration?
Vesna [10]

Answer:

0.05\ \text{M HCl}

Explanation:

V_1 = Initial volume = 100 mL

V_2 = Final volume = 1000 mL

M_1 = Initial concentration = 0.5 M

M_2 = Final concentration

We have the relation

\dfrac{M_1}{M_2}=\dfrac{V_2}{V_1}\\\Rightarrow M_2=M_1\dfrac{V_1}{V_2}\\\Rightarrow M_2=0.5\times \dfrac{100}{1000}\\\Rightarrow M_2=0.05\ \text{M HCl}

The new concentration is 0.05\ \text{M HCl}.

3 0
3 years ago
Metallic copper is formed when aluminum reacts with copper(II) sulfate according to the
katovenus [111]

Answer: Given the equation for reaction is

2 A l +C u S O 4 → A l 2 ( S O 4 ) 3 + 3 C u .

Explanation:

3 0
2 years ago
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