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Savatey [412]
3 years ago
6

Which landforms might you see at a divergent plate boundary? Check all that apply. mid-ocean ridge mountain range rift valley vo

lcano island
Chemistry
2 answers:
Vesnalui [34]3 years ago
7 0

Answer:

a and c

Explanation:

Gwar [14]3 years ago
5 0

Answer:

A. mid-ocean ridge

C. rift valley

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When placed in a 100mL cube shaped box a substance fills the cube and has a volume of 100 mL. When places in a 50mL tube that sa
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There are five states of matter out of which we encounter three states of matter in our day today life

a) gas b) solid and c) liquid

the main difference between the three is of

a) Inter molecular forces of attraction

b) thermal energy

due to this

a) solid has high intermolecular forces and low thermal energy: thus they have fix shape and occupy fix volume

b) liquid has intermediate forces and medium themal energy. Thus they may have fixed volume and but no fix shape

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so in the given problem

the state of the substance D- Gas.

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3 years ago
Percocet contains oxycodone at varying strengths.Every strength also contains 325 mg of
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5.56 Rhats The right answer
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2 years ago
determine the freezing point depression of a solution that contains 30.7 g glycerin (c3h8o3, molar mass
Blababa [14]

The freezing point depression of a solution containing 30.7 g of glycerin  is  calculated as -1.65°C

Equating :

It is given that,

Given mass of glycerin is = 30.7 grams (Solute)

Volume of water = 376 mL

K_{f}or molar -freezing-depression point is = 1.86°C/m

Molar mass of glycerin = 92.09 g/mole

Now, to work out the value, the mass of water should be known. Thus, to calculate, the formula used will be:

Mass = Density X Volume

Mass = 1.0 g/mL X 376 mL

Mass = 376 g or 0.376 Kg

Using the formula of melting point depression, the equation becomes:

             ΔT_{f} = i ×K_{f} ×m

T⁰-T_{s}  = i *K_{f} *\frac{mass of glycerin}{molar mass of glycerin * mass of water     in     kg}

in which,

ΔT_{f} = change in freezing point

ΔT_{s} = freezing point of solution that has to be find

ΔT° = freezing point of water ()

Since, glycerin is a non-electrolyte, the Van't Hoff factor will be 1.

Substituting the values in the above equation:

0⁰C₋T_{s} = 1 ×1.86°C/m ×\frac{30.7}{92.09g/mol * 0.376kg}

T_{s} = -1.65°C

Thus, the freezing point depression of a solution is  -1.65°C

<h2 />

Freezing point depression

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all less than that of the pure solvent and is directly proportional to the molality of the solute

Is melting point elevation or depression?

Boiling point elevation is that the raising of a solvent's boiling point due to the addition of a solute. Similarly, melting point depression is the lowering of a solvent's freezing point due to the addition of a solute. In fact, because the boiling point of a solvent increases, its melting point decreases

Learn more about freezing point depression :

brainly.com/question/26525184

#SPJ4

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9 months ago
True or false. Large covalent molecules with the same molecular formula or more likely to have identical angles between orbitals
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True, because the large covalent molecules would combine with the others
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3 years ago
When molten rock undergoes crystallization above ground, what type of rock results?
vodka [1.7K]
I am pretty sure that the answer is B. extrusive rock. I hope that this helps you!! Good Luck!!
5 0
3 years ago
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