Help with math question plz. 12th grade

Mathematics

1 answer:

leonid [27]3 years ago

4 0

Answer:

Step-by-step explanation:

To find the volume of a rectangular prism, you need to multiply the width by the length by the height (the three given side lengths).

Only C and D do that. Meanwhile A and B just add them, which is not what you're supposed to do.

So, we know it's not A or B.

After finding the volume of each of the prisms, you need to add them to find the combined volume.

D multiplies them, so it's not D.

Therefore it must be C, which correctly multiplies the side lengths and then adds the volumes together at the end.

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the distance around a track is 400m. if you take 14 laps around the track what is the total distance you walk? use mental math

Olegator [25]

to do it in mental math: you can ignore the zeroes in 400 for now.

4*14 = 4*10 + 4*4 = 40 + 16 = 56

now add the zeroes back on: 5600m

6 0

2 years ago

Read 2 more answers

The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir

Paha777 [63]

Answer:

95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean time = 5.15 years

$\sigma$ = sample standard deviation = 1.68 years

n = sample of college graduates = 4400

$\mu$ = population mean time

Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95