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andreyandreev [35.5K]
3 years ago
5

Will mark brainliest :)

Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0

Answer:

D

Step-by-step explanation:

The equation of the parabola is of the form

y = ax² + c ( where c is the y- intercept )

Here c < 0

Since the parabola has a maximum value and opens down then a < 0

Thus the only equation that could represent this parabola is

y = - x² - 3 → D

You might be interested in
4. Find the percent of increase from 56 to 70. Round your answer
notsponge [240]

Answer:

25%

Step-by-step explanation:

6 0
3 years ago
Please help me with question number 2
Mice21 [21]

Answer:

2. The area of the side walk is approximately 217 m²

3. The distance away from the sprinkler the water can spread is approximately 11 feet

4. The area of the rug is 49.6

Step-by-step explanation:

2. The dimensions of the flower bed and the sidewalks are;

The diameter of the flower bed = 20 meters

The width of the circular side walk, x = 3 meters

Therefore, the diameter of the outer edge of the side walk, D, is given as follows

D = d + 2·x (The width of the side walk is applied to both side of the circular diameter)

∴ D  = 20 + 2×3 = 26

The area of the side walk = The area of the sidewalk and the side walk = The area of the flower bed

∴ The area of the side walk, A = π·D²/4 - π·d²/4

∴ A = 3.14 × 26²/4 - 3.14 × 20²/4 = 216.66

By rounding to the nearest whole number, the area of the side walk, A ≈ 217 m²

3. Given that the area formed by the circular pattern, A = 379.94 ft.², we have;

Area of a circle = π·r²

∴ Where 'r' represents how far it can spread, we have;

π·r² = 379.94

r = √(379.94 ft.²/π) ≈ 10.997211 ft.

Therefore, the distance away from the sprinkler the water can spread, r ≈ 11 feet

4. The circumference of the rug = 24.8 meters

The circumference of a circle, C = 2·π·r

Where;

r = The radius of the circle

π = 3.1

∴ For the rug of radius 'r', C = 2·π·r = 24.8

r = 24.8/(2·π) = 12.4/π = 12.4/3.1 = 4

The area = π·r²

∴ The area of the rug = 3.1 × 4² = 49.6.

8 0
3 years ago
The Salk polio vaccine experiment in 1954 focused on the effectiveness of the vaccine in combating paralytic polio. Because it w
sdas [7]

Answer:

Step-by-step explanation:

Hello!

The variables of interest are:

X₁: Number of cases of polio observed in kids that received the placebo vaccine.

n₁= 201299 total children studied

x₁= 110 cases observed

X₂: Number of cases of polio observed in kids that received the experimental vaccine.

n₂= 200745 total children studied

x₂= 33 cases observed

These two variables have a binomial distribution. The parameters of interest, the ones to compare, are the population proportions: p₁ vs p₂

You have to test if the population proportions of children who contracted polio in both groups are different: p₂ ≠ p₁

a)

H₀: p₂ = p₁

H₁: p₂ ≠ p₁

α: 0.05

Z= \frac{(p'_2-p'_1)-(p_2-p_1)}{\sqrt{p'[\frac{1}{n_1} +\frac{1}{n_2} ]} }

Sample proportion placebo p'₁= x₁/n₁= 110/201299= 0.0005

Sample proportion vaccine p'₂= x₂/n₂= 33/200745= 0.0002

Pooled sample proportion p'= (x₁+x₂)/(n₁+n₂)= (110+33)/(201299+200745)= 0.0004

Z_{H_0}= \frac{(0.0002-0.0005)-0}{\sqrt{0.0004[\frac{1}{201299} +\frac{1}{200745} ]} }= -4.76

This test is two-tailed, using the critical value approach, you have to determine two critical values:

Z_{\alpha/2}= Z_{0.025}= -1.96

Z_{1-\alpha /2}= Z_{0.975}= 1.96

Then if Z_{H_0} ≤ -1.96 or if Z_{H_0} ≥ 1.96, the decision is to reject the null hypothesis.

If -1.96 < Z_{H_0} < 1.96, the decision is to not reject the null hypothesis.

⇒ Z_{H_0}= -4.76, the decision is to reject the null hypothesis.

b)

H₀: p₂ = p₁

H₁: p₂ ≠ p₁

α: 0.01

Z= \frac{(p'_2-p'_1)-(p_2-p_1)}{\sqrt{p'[\frac{1}{n_1} +\frac{1}{n_2} ]} }

The value of Z_{H_0}= -4.76 doesn't change, since we are working with the same samples.

The only thing that changes alongside with the level of significance is the rejection region:

Z_{\alpha /2}= Z_{0.005}= -2.576

Z_{1-\alpha /2}= Z_{0.995}= 2.576

Then if Z_{H_0} ≤ -2.576or if Z_{H_0} ≥ 2.576, the decision is to reject the null hypothesis.

If -2.576< Z_{H_0} < 2.576, the decision is to not reject the null hypothesis.

⇒ Z_{H_0}= -4.76, the decision is to reject the null hypothesis.

c)

Remember the level of significance (probability of committing type I error) is the probability of rejecting a true null hypothesis. This means that the smaller this value is, the fewer chances you have of discarding the true null hypothesis. But as you know, you cannot just reduce this value to zero because, the smaller α is, the bigger β (probability of committing type II error) becomes.

Rejecting the null hypothesis using different values of α means that there is a high chance that you reached a correct decision (rejecting a false null hypothesis)

I hope this helps!

8 0
3 years ago
Using the following equation, find the center and radius: x2 −2x + y2 − 6y = 26 (5 points)
Lisa [10]

Answer:

Center: (1,3)

Radius: 6

Step-by-step explanation:

Hi there!

x^2-2x + y^2 - 6y = 26

Typically, the equation of a circle would be in the form (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius.

To get the given equation x^2-2x + y^2 - 6y = 26 into this form, we must complete the square for both x and y.

<u>1) Complete the square for x</u>

Let's take a look at this part of the equation:

x^2-2x

To complete the square, we must add to the expression the square of half of 2. That would be 1² = 1:

x^2-2x+1

Great! Now, let's add this to our original equation:

x^2-2x+1+y^2-6y = 26

We cannot randomly add a 1 to just one side, so we must do the same to the right side of the equation:

x^2-2x+1+y^2-6y = 26+1\\x^2-2x+1+y^2-6y = 27

Complete the square:

(x-1)^2+y^2-6y = 27

<u>2) Complete the square for y</u>

Let's take a look at this part of the equation (x-1)^2+y^2-6y = 27:

y^2-6y

To complete the square, we must add to the expression the square of half of 6. That would be 3² = 9:

y^2-6y+9

Great! Now, back to our original equation:

(x-1)^2+y^2-6y+9= 27

Remember to add 9 on the other side as well:

(x-1)^2+y^2-6y+9= 27+9\\(x-1)^2+y^2-6y+9= 36

Complete the square:

(x-1)^2+(y-3)^2= 36

<u>3) Determine the center and the radius</u>

(x-1)^2+(y-3)^2= 36

(x-h)^2+(y-k)^2=r^2

Now, we can see that (1,3) is in the place of (h,k). 36 is also in the place of r², making 6 the radius.

I hope this helps!

3 0
3 years ago
Read 2 more answers
10 4 4) Maureen has spent 12 9/10hours tutoring students in math and 6 3/4 tutoring students in science, Which choice is the bes
Slav-nsk [51]

Answer:

(C) 20 Hours

Step-by-step explanation:

7 0
3 years ago
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