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3 years ago

Pls help need it for tommorow

Mathematics

2 answers:

ANEK [815]3 years ago

7 0

Step-by-step explanation:

$\frac{3}{10 } = .3$

Ede4ka [16]3 years ago

3 0

Answer:

0.3? because it's one 0 and so you move it once, to the left

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Rewrite 19/5 as a mixed number.

Ugo [173]

19/5 as a mixed number is 3 4/5.

3 0

3 years ago

The volume of a cone is given by v=13πr2h. If a cone has volume 3π, what is the height of the cone when the radius is 12?

Varvara68 [4.7K]

Answer:

16units

Step-by-step explanation:

Given data

The expression for the volume of a cone is given as

v=1/3πr^2h

v= 3π

r= 12

h=???

Substitute

3π= 1/3*π*12^2*h

3= 1/3*144*h

3= 144h/3

cross multiply

3*3= 144h

9= 144h

h= 144/9

h=16 units

Hence the heeight is 16units

3 0

3 years ago

WILL MARK YOU BRAINLIEST JUST GIVE THE ANSWER!!

Igoryamba

Your answer would be the second option

7 0

3 years ago

Read 2 more answers

PLEASE HELP WILL GIVE BRAINLIEST! What is the following sum? Assume x > or equal to 0 and y is > or equal to 0.

Ira Lisetskai [31]

Answer:

Option (b) is correct.

The sum of given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ is $2xy\sqrt{y}+2xy^2\sqrt{x}$

Step-by-step explanation:

Given:Expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ .

$\sqrt{x^2y^3}$ can be written as $\sqrt{x^2y^2y}=xy\sqrt{y}$

Also, $2\sqrt{x^3y^4}$ can be written as $2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}$

Now, the given expression becomes,

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

$=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}$ .

Now, adding like term, terms having same variable with same degree.

$=2xy\sqrt{y}+2xy^2\sqrt{x}$ .

Thus, The sum of given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ is $2xy\sqrt{y}+2xy^2\sqrt{x}$

3 0

3 years ago

ALGEBRA PROBLEM PLEASE HELP

Natasha_Volkova [10]

Answer:

B, C, and F are functions

Step-by-step explanation:

4 0

3 years ago

Pls help need it for tommorow​

Pls help need it for tommorow