A book club has 10 members.How many ways can they choose a president, vice president, and secretary from among the members?

2 answers:

8 0

A.
30

B.
120

C.
720

D.
100 720 possible combinations if each post is held by one person.
90 possible combinations if one person can have two positions.
10 possible combinations if one person can hold all three.

igor_vitrenko [27]3 years ago

7 0

Assuming that each person holds 1 positiion

slot metho
3 slots (pres, vice, sec)
1st slot:10 optoins
2nd slot:9 ooptions(1 gone to 1st slot)
3rd slot:8 options (1 gone to 1st and 1 to 2nd)

multiply
10*9*8=720

720 ways

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Licemer1 [7]

Answer:

17/49 or about 34.7%

Step-by-step explanation:

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Read 2 more answers

Molly tried to evaluate 93\times5193×5193, times, 51 using partial products. Her work is shown below.

Mrac [35]

Since molly's solution tally's with the given solution, hence Molly's solution is correct.

Given the working on a partial product of 93 and 51 carried out by Molly as shown:

$\begin{array}{llrr} &&93 \\ &&\underline{{}\times51} \\ &\blueD{\text{Step 1}}&\blueD{3}& \blueD{1\times3\text{ ones}}\\ &\greenD{\text{Step 2}}&\greenD{90}& \greenD{1\times 9\text{ tens}}\\ &\maroonD{\text{Step 3}}&\maroonD{150}& \maroonD{50\times 3\text{ ones}}\\ &\goldE{\text{Step 4}}&\underline{{}+\goldE{ 4{,}500}}& \goldE{50\times 9\text{ tens}}\\ &\purpleD{\text{Step 5}}&\purpleD{4{,}743}& \end{array}$