Question

write an equation of the line passing through point p that is perpendicular to the given line p(6,10),y=-3x+13

Answer 1

Answer:

y = $\frac{1}{3}$ x + 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - 3x + 13 is in this form

with m = - 3

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-3}$ = $\frac{1}{3}$

y = $\frac{1}{3}$ x + c ← is the partial equation

To find c substitute (6, 10) into the partial equation

10 = 2 + c ⇒ c = 10 - 2 = 8

y = $\frac{1}{3}$ x + 8 ← equation of line